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3 years ago

an art supply store sells posters for 9$ and picture frames for 15$. what is the total cost for 6 framed posters?

Mathematics

2 answers:

myrzilka [38]3 years ago

7 0

The total cost of 6 frames is going to be 90 dollars.You multiply 15 ,times 6

Evgen [1.6K]3 years ago

6 0

69 framed posters beacuse you have to add 9 and 15 and multiply 24 times 6

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ILL GIVE BRAINLIEST HELP PLEASE

PilotLPTM [1.2K]

The solution to the system of equation is (1, 4).

In order to find this, we can first just see where the graphs intersect each other. This will give us the solution set.

As for what it represents, the x value in the increase in temperature and the y value is the increase in customers.

Therefore, we know that we want the temperature to go up by 1 (although we don't know the units) and that would result in the amount of people coming, and staying longer by 4 (again, we don't know the units of measure).

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3 years ago

Find the sale price

Nimfa-mama [501]

24.5x.18=4.41

$4.41 is how much you save with the discount. You subtract this amount from the regular price.

24.5-4.41=20.09

The sale price of the item should be $20.09

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3 years ago

Which correctly represents the probability 1 as a percent?

In-s [12.5K]

Answer:

0.01

Step-by-step explanation:

if you meant a to be .01 than it's that good luck

5 0

3 years ago

Read 2 more answers

velikii [3]

Given data:

Volume of the prism A = 2080 $c m^{3}$

Let us find the ratio of the volume of prisms given in the diagram:
$\frac{ V_{A}}{V_{B}} = \frac{8^{3}}{4^{3}}$
$\frac{ V_{A}}{V_{B}} = 8$

Since the condition is:
The volume of Prism A = The volume of Prism B
Therefore,
The ratio of their volumes should be 8.
$\frac{ V_{A}}{V_{B}} =8$

Since Volume of A = 2080 $cm^{3}$

Plug-in the value, you would get:

$\frac{2080}{8}} = V_{B}$

Ans: Volume of B = 260 $cm^{3}$

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3 years ago

The bottoms of two vertical poles are 12 feet apart and are on a region of flat ground. One pole is 6 feet tall and the other is

snow_tiger [21]

Answer:

The length of the wire is 15 ft.

Step-by-step explanation:

The solution of this exercise comes from an application of the Pythagorean theorem. The explanation here is complemented with the figure attached.

In the figure the segments AB and CD represents the vertical poles, where the length of AB is 6 ft and the length of CD is 15 ft. We want to find the length of the segment BD, that represents the stretched wire. The length of the segment AC is 12 ft, which is the distance between the poles.

If we draw an imaginary line from A perpendicular to DC, we obtain a rectangle ABEC, and a right triangle BED. Then, the length of BE is 12 ft. Moreover, the length of CE is 6 ft, because is equal to the length of AB. Hence, the length of DE is 9 ft, because DE = DC-EC.

As we want to find the length of the hypotenuse BD of the right triangle BED, and we already have the lengths of the other two sides, we only need to apply the Pythagorean theorem. This is

$BD^2 = BE^2 + ED^2 = 12^2+9^2= 144+81=225.$

Then, taking square roots in both sides: BD=15 ft.

6 0

3 years ago