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3 years ago

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one day, bill at the candy shoo sold 210 bottles of cherry soda and grape soda for a total of 230.30. If the cherry soda costs 1

.15 and the grape soda costs $.99, how many of each kind where sold

1 answer:

oksian1 [2.3K]3 years ago

5 0

Mmmmmmmm””6098876544

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Solve the following quadratic function by utilizing the square root method. f(x) = 1 - x2 x = + [?]

faltersainse [42]

Answer:

Step 1) y=16-x2. Swap the sides so that all terms of the variables are on the left side. Step 2) 16-x_{2}=y. Subtract 16 from both sides. Step 3) -x_{2}=y-16 Divide the two sides by -1. Step 4). \frac{-x_{2}}{-1}=\frac{y-16}{-1} Dividing by -1 undoes the multiplication by -1. Step 5). x_{2}=\frac{y-16}{-1} Step 6) dived y-16 by -1 And the final answer = x_{2}=16-y

Step-by-step explanation:

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2 years ago

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PLEASE HELP NEED THE ANSWER IMMEDIATELY!

vesna_86 [32]

$\textsf{\qquad\qquad\huge\underline{{\sf Answer}}}$

Volume of a rectangular prism is ~

$\sf{Volume_{cuboid}= Length × Width × Height}$

$\qquad \sf \dashrightarrow \: v = (4x + 2) \times (3x - 5) \times (7x + 4)$

$\qquad \sf \dashrightarrow \: v = (12 {x}^{2} - 20x + 6x - 10) \times (7x + 4)$

$\qquad \sf \dashrightarrow \: v = (12 {x}^{2} - 14x- 10) \times (7x + 4)$

$\qquad \sf \dashrightarrow \: v = 84 {x}^{3} + 48 {x}^{2} - 98x {}^{2} - 56x - 70x - 40$

$\qquad \sf \dashrightarrow \: v = 84 {x}^{3} - 50 {x}^{2} - 126x - 40$

So, the correct choice is B

7 0

2 years ago

Simple interest can be found by using the formula I= prt, where 1= interest, p=principle, r=rate, and t=time. Solve for principl

sveta [45]

I =PRT

solve for P

divide both sides by RT

I/RT = P

4 0

3 years ago

Please help me with these questions

Nonamiya [84]

Answer:

9) u= -12

11) -18 over 2

Step-by-step explanation:

Hope this helps!!

3 0

3 years ago

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Please someone help me...

laiz [17]

Step-by-step explanation:

First factor out the negative sign from the expression and reorder the terms

That's

$\frac{1}{ - (( \tan(2A) - \tan(6A) )} - \frac{1}{ \cot(6A) - \cot(2A) }$

<u>Using trigonometric </u><u>identities</u>

That's

<h3> $\cot(x) = \frac{1}{ \tan(x) }$ </h3>

<u>Rewrite the expression</u>

That's

$\frac{1}{ - (( \tan(2A) - \tan(6A) )} - \frac{1}{ \frac{1}{ \tan(6A) } } - \frac{1}{ \frac{1}{ \tan(2A) } }$

We have

<h3> $- \frac{1}{ \tan(2A) - \tan(6A) } - \frac{1}{ \frac{ \tan(2A) - \tan(6A) }{ \tan(6A) \tan(2A) } }$ </h3>

<u>Rewrite the second fraction</u>

That's

<h3> $- \frac{1}{ \tan(2A) - \tan(6A) } - \frac{ \tan(6A) \tan(2A) }{ \tan(2A) - \tan(6A) }$ </h3>

Since they have the same denominator we can write the fraction as

$- \frac{1 + \tan(6A) \tan(2A) }{ \tan(2A) - \tan(6A) }$

Using the identity

<h3> $\frac{x}{y} = \frac{1}{ \frac{y}{x} }$ </h3>

<u>Rewrite the expression</u>

We have

<h3> $- \frac{1}{ \frac{ \tan(2A) - \tan(6A) }{1 + \tan(6A) \tan(2A) } }$ </h3>

<u>Using the trigonometric identity</u>

<h3> $\frac{ \tan(x) - \tan(y) }{1 + \tan(x) \tan(y) } = \tan(x - y)$ </h3>

<u>Rewrite the expression</u>

That's

<h3> $- \frac{1}{ \tan(2A -6A) }$ </h3>

Which is

<h3> $- \frac{1}{ \tan( - 4A) }$ </h3>

<u>Using the trigonometric identity</u>

<h3> $\frac{1}{ \tan(x) } = \cot(x)$ </h3>

Rewrite the expression

That's

<h3> $- \cot( - 4A)$ </h3>

<u>Simplify the expression using symmetry of trigonometric functions</u>

That's

<h3> $- ( - \cot(4A) )$ </h3>

<u>Remove the parenthesis </u>

We have the final answer as

<h2> $\cot(4A)$ </h2>

As proven

Hope this helps you

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3 years ago

Read 2 more answers