Ok so without the distributive property we would do 65*7. All u have to do is spread it out like this:-
65+65+65+65+65+65+65=455
hope i helped u:D
Answer:
The probability that the intersection will come under the emergency program is 0.1587.
Step-by-step explanation:
Lets divide the problem in months rather than in years, because it is more suitable to divide the period to make a better approximation. If there were 36 accidents in average per year, then there should be 3 accidents per month in average. We can give for the amount of accidents each month a Possion distribution with mean 3 and variance 3.
Since we want to observe what happen in a period of one year, we will use a sample of 12 months and we will take its mean. We need, in average, more than 45/12 = 3.75 accidents per month to confirm that the intersection will come under the emergency program.
For the central Limit theorem, the sample mean will have a distribution Normal with mean 3 and variance 3/12 = 0.25; thus its standard deviation is √0.25 = 1/2.
Lets call the sample mean distribution X. We can standarize X obtaining a standard Normal random variable W with distribution N(0,1).

The values of
, the cummulative distribution function of W, can be found in the attached file. We are now ready to compute the probability of X being greater than 3.75, or equivalently, the probability than in a given year the amount of accidents is greater than 45, leading the intersection into an emergency program

Answer:
y=4x-4
slope of the line=-4/-1
4/1
since perpendicular,
m1.m2=-1
4.m2=-1
m2=-1/4
The equation of line passing through the point (4,2)is
y-y1=m2(x-x1)
y-2=-1/4(x-4)
Step-by-step explanation:
i don't say that you have to mark my ans as brainliest but my friend if it has helped you a bit also don't forget to thank me.....
Answer: 200+40x=600
Step-by-step explanation:
200+40x=600
600-200=400
40x=400
40/40= 1 or x
400/ 40=10
x=10