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stira [4]
3 years ago
12

Identify the type of conic section that is represented by the equation y^2- 1 = 4(x-7). DUE IN 2 HOURS, will give BRAINLIEST! A.

Circle B. Hyperbola C. Parabola D. Ellipse

Mathematics
1 answer:
Elenna [48]3 years ago
8 0

Answer:

Solution : Parabola

Step-by-step explanation:

As you can see only one variable is square in this situation, so it can only be a parabola. We can prove that it is a parabola however by converting it into standard form (x - h)^2 + (y - k)^2.

y^2-1=4\left(x-7\right) = y^2-1=4\left(x-7\right)

Respectively it's properties would be as follows,

\left(h,\:k\right)=\left(\frac{27}{4},\:0\right),\:p=1

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Please help me<br> Show your work
GrogVix [38]

<u>ANSWER TO PART A</u>

The given triangle has vertices J(-4,1), K(-4,-2),L(-3,-1)


The mapping for rotation through 90\degree counterclockwise has the mapping


(x,y)\rightarrow (-y,x)


Therefore

J(-4,1)\rightarrow J'(-1,-4)


K(-4,-2)\rightarrow K'(2,-4)


L(-3,-1)\rightarrow L'(1,-3)


We plot all this point and connect them with straight lines.


ANSWER TO PART B


For a reflection across the y-axis we negate the x coordinates.


The mapping is



(x,y)\rightarrow (-x,y)


Therefore

J(-4,1)\rightarrow J''(4,1)


K(-4,-2)\rightarrow K''(4,-2)


L(-3,-1)\rightarrow L''(3,-1)


We plot all this point and connect them with straight lines.


See graph in attachment







7 0
3 years ago
Recall that m(t) = (1/2)^t/h for radioactive decay, where h is the half-life. Suppose that a 500g sample of phosphorus-32 decays
katrin2010 [14]

The question is incomplete, here is the complete question:

Recall that m(t) = m.(1/2)^t/h for radioactive decay, where h is the half-life. Suppose that a 500 g sample of phosphorus-32 decays to 356 g over 7 days. Calculate the half life of the sample.

<u>Answer:</u> The half life of the sample of phosphorus-32 is 14.28days^{-1}

<u>Step-by-step explanation:</u>

The equation used to calculate the half life of the sample is given as:

m(t)=m_o(1/2)^{t/h}

where,

m(t) =  amount of sample after time 't' = 356 g

m_o = initial amount of the sample = 500 g

t = time period = 7 days

h = half life of the sample = ?

Putting values in above equation, we get:

356=500\times (\frac{1}{2})^{7/h}\\\\h=14.28days^{-1}

Hence, the half life of the sample of phosphorus-32 is 14.28days^{-1}

7 0
3 years ago
У
kramer
Value of y= 18 and value of x= 9 root3
therefore answer is D
7 0
2 years ago
Can someone help me with this
ludmilkaskok [199]

Answer:

A

Step-by-step explanation:

1/2r +1/2= -2/7r  -29/7 Subtracting 1/2 from both sides

1/2r +1/2 - 1/2= -2/7r  -29/7- 1/2

1/2r = -2/7r  - 29(2)-7/14

1/2r = -2/7r  -65/14

3 0
2 years ago
What are the slope and the y-intercept of the linear function that is represented by the equation y=-10x+1
RUDIKE [14]
<h3>Answer:</h3>

The slope is -10 and the y-intercept is 1.

<h3>Explanation:</h3>

This function is written in slope-intercept form, which is y=mx+b.  In this form, m is the slope and b is the y-intercept.

In this case, m=-10 and b=1, so those are the answers to this problem.

6 0
3 years ago
Read 2 more answers
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