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Irina-Kira [14]

3 years ago

11

In Raiders of the Lost Ark, Indiana Jones tried to remove a gold idol from a trapped pedestal. He replaces the idol with a bag o

f sand. If the idol has a mass of 2.00 kg, how many liters of sand must he place on the pedestal to keep he mass sensitive trap from activating? (Density of sand is 3.00 g.cm^3)

2 answers:

Greeley [361]3 years ago

4 0

Answer:

2/3 liter

Step-by-step explanation:

3.00 g/cm³ = 3.00 kg/L . . . . . . . 1000 g = 1 kg; 1000 cm³ = 1 L

For a mass of 2.00 kg, you need ...

(2.00 kg)/(3.00 kg/L) = 2/3 L ≈ 0.667 L

Ivahew [28]3 years ago

4 0

Answer:

6.67×10^-7Litres

Step-by-step explanation:

Density is defined as the ratio of mass of a substance per its unit volume.

Density = Mass/volume

Volume = Mass/Density

Given mass of sand= 2.0kg

Density of sand = 3.0g/cm³

To ensure unit consistency, we can convert 2.0kg to grams

2.0kg = 2000grams

Volume = 2000g/3g/cm³

Volume = 666.67cm³

Converting the volume to m³

1m³ = 10^6cm³

y = 666.67cm³

Cross multiplying

10^6 ×y = 666.7 × 1

y = 666.7/10^6

y = 6.67×10^-4m³

Converting to litres

Since 1000m³ = 1litres

6.67×10^-4m³ = L

1000L = 6.67×10^-4m³

L = 6.67×10^-4/1000

L = 6.67×10^-7Litres

He must place 6.67×10^-7Litres on the pedestal to keep the mass sensitive trap from activating

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The first term of a geometric sequence is 15, and the 5th term of the sequence is <img src="https://tex.z-dn.net/?f=%5Cfrac%7B24

sladkih [1.3K]

The geometric sequence is $15,9,\frac{27}{5},\frac{81}{25}, \frac{243}{125}$

Explanation:

Given that the first term of the geometric sequence is 15

The fifth term of the sequence is $\frac{243}{125}$

We need to find the 2nd, 3rd and 4th term of the geometric sequence.

To find these terms, we need to know the common difference.

The common difference can be determined using the formula,

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