In Raiders of the Lost Ark, Indiana Jones tried to remove a gold idol from a trapped pedestal. He replaces the idol with a bag o f sand. If the idol has a mass of 2.00 kg, how many liters of sand must he place on the pedestal to keep he mass sensitive trap from activating? (Density of sand is 3.00 g.cm^3)
2 answers:
Answer:
2/3 liter
Step-by-step explanation:
3.00 g/cm³ = 3.00 kg/L . . . . . . . 1000 g = 1 kg; 1000 cm³ = 1 L
For a mass of 2.00 kg, you need ...
(2.00 kg)/(3.00 kg/L) = 2/3 L ≈ 0.667 L
Answer:
6.67×10^-7Litres
Step-by-step explanation:
Density is defined as the ratio of mass of a substance per its unit volume.
Density = Mass/volume
Volume = Mass/Density
Given mass of sand= 2.0kg
Density of sand = 3.0g/cm³
To ensure unit consistency, we can convert 2.0kg to grams
2.0kg = 2000grams
Volume = 2000g/3g/cm³
Volume = 666.67cm³
Converting the volume to m³
1m³ = 10^6cm³
y = 666.67cm³
Cross multiplying
10^6 ×y = 666.7 × 1
y = 666.7/10^6
y = 6.67×10^-4m³
Converting to litres
Since 1000m³ = 1litres
6.67×10^-4m³ = L
1000L = 6.67×10^-4m³
L = 6.67×10^-4/1000
L = 6.67×10^-7Litres
He must place 6.67×10^-7Litres on the pedestal to keep the mass sensitive trap from activating
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