Question

In Raiders of the Lost Ark, Indiana Jones tried to remove a gold idol from a trapped pedestal. He replaces the idol with a bag of sand. If the idol has a mass of 2.00 kg, how many liters of sand must he place on the pedestal to keep he mass sensitive trap from activating? (Density of sand is 3.00 g.cm^3)

Answer 1

Answer:

  2/3 liter

Step-by-step explanation:

3.00 g/cm³ = 3.00 kg/L . . . . . . . 1000 g = 1 kg; 1000 cm³ = 1 L

For a mass of 2.00 kg, you need ...

  (2.00 kg)/(3.00 kg/L) = 2/3 L ≈ 0.667 L

Answer 2

Answer:

6.67×10^-7Litres

Step-by-step explanation:

Density is defined as the ratio of mass of a substance per its unit volume.

Density = Mass/volume

Volume = Mass/Density

Given mass of sand= 2.0kg

Density of sand = 3.0g/cm³

To ensure unit consistency, we can convert 2.0kg to grams

2.0kg = 2000grams

Volume = 2000g/3g/cm³

Volume = 666.67cm³

Converting the volume to m³

1m³ = 10^6cm³

y = 666.67cm³

Cross multiplying

10^6 ×y = 666.7 × 1

y = 666.7/10^6

y = 6.67×10^-4m³

Converting to litres

Since 1000m³ = 1litres

6.67×10^-4m³ = L

1000L = 6.67×10^-4m³

L = 6.67×10^-4/1000

L = 6.67×10^-7Litres

He must place 6.67×10^-7Litres on the pedestal to keep the mass sensitive trap from activating