Answer:
Hello Sir/ Mam
YOUR REQUIRED ANSWER IS 18.6%
Variables defined in the question:
H - Home - Games
W - Winning Games
Now, given:
P(H0.62 PW)0.22
P(W\mid H)=0.30
Required : Of all the games, percentage of games that were at home wins.
Hence, required :
P(W\cap H)
Now, we know that:
P(W\mid H)=\frac{P(W\cap H)}{P(H)}
0.3=\frac{P(W\cap H)}{0.62}
Hence,
P(W\cap H)=0.3*0.62=0.186=18.6\%
I hope this solves your doubt.
Feel free to comment if you still have any query.
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Step-by-step explanation:
Nice so
remember
t=d/s
a(b+c)=ab+ac
time=distance/speed
lets say s=jamie's normal speed
speed agains wind=s-4
speed with wind=s+4
30 miles is agains wind
distance is 54 with wind
t=d/s
t=30/(s-4)
t=54/(s+4)
since they are both equal to t, set them equal to each other
30/(s-4)=54/(s+4)
multipliy both sides by (s+4)(s-4)
30(s+4)=54(s-4)
distribute
30s+120=54s-216
subtract 30s from both sides
120=24s-216
add 216 to both sides
336=24s
divide both sides by 24
14=s
answer is 14 miles per hour without wind
Part 1: Equivalent fraction=3/500
Equivalent Decimal= .006
Part 2: A and E
Divide 47 by 100. you will get a decimal. move the decimal two places the right and there is your percent!
Q represents how many they did NOT recieve
380-127= 253
Now let's check
380-253= 127
CHECK
So q represents 253(the number of invitations they did NOT recieve)
Hope this helps!
