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bonufazy [111]
3 years ago
12

PLS PLS PLS HELP IM BEHIND The first sequence rule is multiply by 3 starting from 4. The second sequence rule is add 8 starting

from 20. What is the first number that appears in both sequences?
12
20
28
36
Mathematics
1 answer:
Alchen [17]3 years ago
6 0

Answer:

36

Step-by-step explanation:

the first sequence starts

4 12 (3*4) 36 (3*12) 108 (3*36) ...

the second sequence starts

20 28 (8+20) 36 (8+28) 44 (8+36) ...

so, just by writing down a few elements you can see it already.

I knew it already before that just by thinking "the first sequence has only numbers that can be divided by 3. what is the first number of the second sequence that can be also divided by 3 ? oh, yeah, 36 !"

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Round to the nearest million 123,045,067
podryga [215]

Answer:

123,000,000

Step-by-step explanation:

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I hope this helps and please don't hesitate to ask if there is anything still unclear!

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3 years ago
Razionalisacion de denominadores 3 v3 tres sobre raiz cuadrada de 3
Fiesta28 [93]

Answer:

√3

Step-by-step explanation:

Spanish

Racionalización de denominadores 3 / v3 tres sobre raíz cuadrada de 3

da

Usando el método de índices

3 / √3 = 3¹ / 3¹ / ²

= 3¹ / 3⁰.⁵

= 3¹⁻¹ / ²

= 3 ¹ / ²

= √3

Esto también se puede resolver multiplicando tanto el numerador como el denominador por √3

3 / √3 * √3 / √3

= 3√3 / √3 * 3

= 3√3 / √9

= 3√3 / 3

Los tres se cancelan y nos queda √3

English

Rationalization of denominators 3 /v3 three over square root of 3

gives

Using the method of indices

3 / √3 = 3¹/ 3¹/²

= 3¹/ 3⁰.⁵

= 3¹⁻¹/²

=3 ¹/²

=√3

This can also be solved multiplying both the numerator and the denominator by √3

3 / √3 * √3/√3

= 3√3/ √3*3

= 3√3/ √9

= 3√3/ 3

The three are cancelled and we are left with √3

6 0
3 years ago
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