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jarptica [38.1K]
4 years ago
7

Round these prices to the nearest pound.

Mathematics
1 answer:
amm18124 years ago
7 0
£1100, £3, £88, £376, £300, £44
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What is 9 1/10 - 4 3/4
Nady [450]

Answer:

\frac{87}{20}

Step-by-step explanation:

First we need to change the mixed numbers into improper fractions.

9 x 10 = 90 + 1 = 91/10

4 x 4 = 16 + 3 = 19/4

Now we need to get them into simplest terms. There is a few ways to do this, but I know that 10 x 2 = 20 and 4 x 5 = 20 so I will use 20.

\frac{91}{10} = \frac{91 x 2}{10 x 2} = \frac{182}{20}

\frac{19}{4} = \frac{19 x 5}{4 x 5} = \frac{95}{20}

Now we can subtract:

\frac{182}{20} - \frac{95}{20} = \frac{87}{20}

And that leaves us with our answer :D

5 0
3 years ago
Can someone help me? ‍
Sever21 [200]

Answer:

1.5

Step-by-step explanation:

divide the bigger numbers by the smaller numbers, giving us 1.5 for each division

7 0
3 years ago
Tom has a water tank that holds 5 gallons of water. Tom uses water from a full tank to fill 6 bottles that each hold 16 ounces a
kondor19780726 [428]
A gallon is 128 fluid ounces, so there were 640 ounces in Tom's full tank.

He filled a total volume of
.. 6*16 +(1/2)*128 = 96 +64 = 160 ounces
The tank has left
.. 640 -160 = 480 . . . . ounces of water
4 0
4 years ago
Graph f(x) = -x-3.<br> Use the line tool and select two points to graph the line.
FrozenT [24]

Answer: Look at the screenshot

Step-by-step explanation:

Ive added a screenshot of what this graph should look like

4 0
2 years ago
Read 2 more answers
PRECALCULUS<br> Please look at every picture and answer all questions, thanks.
Marta_Voda [28]
1. so it has to have every x is one y and every y has one x
graph them
we see that the only ones that are one to one are the first one, the 2nd one and the 4th one

2.
solve for x and replace with f⁻¹(x) and y with x
minus 8 and cube both sides
(y-8)³=x-2
add 2
(y-8)³+2=x
replace
f⁻¹(x)=(x-8)³+2
first one


3.
this is a one to one function because theer is no vertical line that could intersect the graph more than once
ah, I see, you're program has a different one to one definition, no horizontal or vertical line can cross, lemme edit te first question again
answer is 2nd option


4. a neat trick is this:
the domain of f(x) is the range of f⁻¹(x)
the range of f(x) is the domain of f⁻¹(x)

the domain of f(x)=1/(3x+2)
hmm, can't divide by 0 so set denomenator to 0
3x+2=0
3x=-2
x=-2/3
domain is all real numbers except -2/3
(-infinity,-2/3)U(-2/3,infinity)
that's the range of f⁻¹(x)

range
ok, hmm, range is from positive initny to 0 then from 0 to positive inifnty, not including 0

so the domain of f⁻¹(x) is (-∞,0)U(0,∞)
range of f⁻¹(x) is (-∞,-2/3)U(-2/3,∞)
first option
8 0
3 years ago
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