Question

Solve the equation -x^2+50=25

Answer 1

Answer:

Two solutions were found :

x = 5

x = -5

Step-by-step explanation:

Step  1  :

Trying to factor as a Difference of Squares :

1.1      Factoring:  25-x2

Theory : A difference of two perfect squares,  A2 - B2  can be factored into  (A+B) • (A-B)

Proof :  (A+B) • (A-B) =

        A2 - AB + BA - B2 =

        A2 - AB + AB - B2 =

        A2 - B2

Note :  AB = BA is the commutative property of multiplication.

Note :  - AB + AB equals zero and is therefore eliminated from the expression.

Check :  25  is the square of  5

Check :  x2  is the square of  x1

Factorization is :       (5 + x)  •  (5 - x)

Equation at the end of step  1  :

 (x + 5) • (5 - x)  = 0

Step  2  :

Theory - Roots of a product :

2.1    A product of several terms equals zero.

When a product of two or more terms equals zero, then at least one of the terms must be zero.

We shall now solve each term = 0 separately

In other words, we are going to solve as many equations as there are terms in the product

Any solution of term = 0 solves product = 0 as well.

Solving a Single Variable Equation :

2.2      Solve  :    x+5 = 0

Subtract  5  from both sides of the equation :

                     x = -5

Solving a Single Variable Equation :

2.3      Solve  :    -x+5 = 0

Subtract  5  from both sides of the equation :

                     -x = -5

Multiply both sides of the equation by (-1) :  x = 5

Two solutions were found :

x = 5

x = -5

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Answer 2

Answer:

x = ±5

Step-by-step explanation:

-x²+50=25   (subtract 50 from both sides)

-x² = 25 - 50

-x² = -25  (multiply both sides by -1)

x² = 25  (take square root of both sides)

x = ±√25   (recall that 5 x 5 = 25)

x = ±5