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igomit [66]
2 years ago
15

Explain why 3 : 2 and 9 : 8 are not equivalent ratios.

Mathematics
2 answers:
maw [93]2 years ago
7 0

Answer:because 2 can’t go into 9 and 8 can’t go into 3

Step-by-step explanation

-

Wewaii [24]2 years ago
4 0

Answer:

3:2 is equal to 12:8 and 12:8 is not 9:8

Step-by-step explanation:

Ratios are also fractions

3/2 is also 12/8

12/8 is not 9/8

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Simplify the expression 3^-8× 34.
Alborosie

Answer:

= \frac{34}{6561}

Step-by-step explanation:

= 3^{-8}\times \:34\\= 34\times \frac{1}{3^{8} } \\= \frac{1\times \:34}{3^{8} } \\= \frac{34}{3^{8} } \\= \frac{34}{6561}

5 0
3 years ago
What is the selling price of an item if the original cost is $784.50 and the markup on the item is 6.5 percent?
JulijaS [17]

Answer:

Solution:

Given, cost price = $784.50

Profit = 6.5% of cost price

        = 6.5/100 × $784.50

        = $50.9925 [since, profit% is always on C.P.]

And selling price = cost price + profit

                      = $784.50 + $50.9925

                      = $835.4925

Hence, selling price = $835.4925

5 0
2 years ago
Read 2 more answers
Solve for x <br> y=-1/2x=3
ANEK [815]

Answer:

-6

Step-by-step explanation:

x=-6

5 0
3 years ago
Substitute the values for a, b, and c into b2 – 4ac to determine the discriminant. Which quadratic equations will have two real
garik1379 [7]

The complete question is

"Substitute the values for a, b, and c into b2 – 4ac to determine the discriminant. Which quadratic equations will have two real number solutions? (The related quadratic function will have two x-intercepts.) Check all that apply.

0 = 2x^2 – 7x – 9

0 = 4x^ 2 – 3x – 1

The quadratic equations that have real number solutions are; 4x^2 – 3x – 1, and 2x^2 – 7x – 9.

<h3>What is the formula for Discriminant?</h3>

The formula for finding the discriminant is

b^2 - 4ac

The solution contains the term \sqrt{b^2 - 4ac} which will be:

Real and distinct if the discriminant is positive

Real and equal if the discriminant is 0

Non-real and distinct roots if the discriminant is negative

For the quadratic equation 2x^2 - 7x - 9

b^2 - 4ac

= (-7) ^2 - 4( 2) ( -9)\\\\= 49 + 72 = 121

This equation has two real number solutions.

For the quadratic equation 4x^ 2 - 3x- 1

b^2 - 4ac

= (-3) ^2 - 4( 4) ( -1)\\\\= 9 + 16 = 25

This equation will have two real number solutions.

Learn more on discriminant here:

brainly.com/question/1537997

#SPJ1

5 0
1 year ago
If QR= 3x-2, RS= 2x+1, QS=6x-3, and R is between Q and S, then RS=​
rewona [7]

Answer:

RS = 5

Step-by-step explanation:

Since R is between Q and S , then

QS = QR + RS , that is

6x - 3 = 3x - 2 + 2x + 1

6x - 3 = 5x - 1 ( subtract 5x from both sides )

x - 3 = - 1 ( add 3 to both sides )

x = 2

Then

RS = 2x + 1 = 2(2) + 1 = 4 + 1 = 5

4 0
3 years ago
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