The answer & explanation for this question is given in the attachment below.
The present age of father is 86 years old and present age of son is 48 years old
<em><u>Solution:</u></em>
Given that, a father is now 38 years older than his son
Ten years ago he was twice as old as his son
Let "x" be the age of son now
Therefore, from given,
Father age now = 38 + age of son now
Father age now = 38 + x
<em><u>Ten years ago he was twice as old as his son</u></em>
Age of son ten years ago = age of son now - 10
Age of son ten years ago = x - 10
Age of father ten years ago = 38 + x - 10
Then we get,
Age of father ten years ago = twice the age of son ten years ago
38 + x - 10 = 2(x - 10)
28 + x = 2x - 20
2x - x = 28 + 20
x = 48
Thus son age now is 48 years old
Father age now = x + 38 = 48 + 38 = 86
Thus present age of father is 86 years old and present age of son is 48 years old
The answer is false due to the object is changes shape not size
Answer:
17
Step-by-step explanation:
| 9- (- 8) | = | 17 | = 17
Basically the absolute value of N1 - N2
Answer:
6 hours
Step-by-step explanation:
Let
x----> the number of hours worked at the donut shop
y----> the number of hours worked at the school bookstore
we know that
x+y=20
x=20-y -----> equation A
10.25x+8.75y=196 -----> equation B
Substitute equation A in equation B and solve for y
10.25(20-y)+8.75y=196
205-10.25y+8.75y=196
10.25y-8.75y=205-196
1.5y=9
y=6 hours at the school bookstore
