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Alekssandra [29.7K]
3 years ago
8

I am a 2 dimensional shape that has four sides. I have four 90 degree angles. I have two sets of parallel lines. I also have two

sides that are one length, and my other two sides are a different length.
Mathematics
1 answer:
Ray Of Light [21]3 years ago
7 0
You are a rhombus sometimes although not correctly referred to as a diamond 
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2. The student council at Camp Creek Middle School determines that 3 out of 4
Gemiola [76]

Answer:

Hi there!

Your answer is:

996 students were apart of this survey!

Step-by-step explanation:

3 out of 4 students means that 75% of students prefer the assemblies be held on Friday.

If 75% = 747 students then:

/75

1% = 9.96 students

×100

100% = 996 students

I hope this makes sense!

8 0
3 years ago
What are the steps for solving v^2+7v+6=0
Ivanshal [37]

Answer:

(v+6)(v+1)

Step-by-step explanation:

You need to factor the equation.

Try plugging in the quadratic formula

4 0
3 years ago
Read 2 more answers
The mean of 100 observation is found to be 40. If at the time of compution two items were wrongly taken as 30 and 27 instead of
Colt1911 [192]

Answer:

40.18

Step-by-step explanation:

According to this question, the mean of 100 observation is found to be 40. This means that the number of values in the set of data is 100. However, at the time of computation two items were wrongly taken as 30 and 27 instead of 3 and 72.

The mean is derived by dividing the sum of values in the data (Σx) by the number of observations (n) i.e.

Mean = Σx/n

For the computation error:

Mean = 40

Let x represent the sun of other 98 values except 30 and 27

n = 100

40 = x + 30 + 27/100

40 = 57 + x/100

Cross multiply

4000 = 57 + x

x = 4000 - 57

x = 3943.

Sum of other 98 values = 3943.

Now, let's find the correct mean with correct values of 3 and 72;

Mean = Σx/n

Mean = 3943 + 3 + 72/100

Mean = 4018/100

Mean = 40.18

7 0
3 years ago
CHEGG The accompanying observations are precipitation values during March over a 30-year period in Minneapolis-St. Paul. 0.32, 0
Marina86 [1]

Answer:

Mean 1.580666667 1.769333333

Standard Deviation 0.890741799 1.123161779

Step-by-step explanation:

When we run the commands in the R software we get the graphs as follows.

The commands were

qqnorm(c(0.32,0.52,0.77,0.81,0.96,1.2,1.31,1.43,1.62,1.87,1.95,2.1,2.48,3,3.37))

and

qqnorm(c(0.47,0.59,0.81,0.9,1.18,1.2,1.35,1.51,1.74,1.89,2.05,2.2,2.81,3.09,4.75))

We can plot the graphs in any other plotting software .

The results would be same .

We see there's a slight difference between the two graphs.

One curve goes above ( Minneapolis) for  0.4 and the other ( for St Paul) is below 0.4

5 0
3 years ago
Which inequality is true?
Aleonysh [2.5K]
D. Will be the correct answer
5 0
3 years ago
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