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almond37 [142]
3 years ago
13

Given z3 = 3 + StartRoot 3 EndRoot ii, which letter represents z?

Mathematics
2 answers:
Ganezh [65]3 years ago
8 0

Answer:

A

Step-by-step explanation:

Right on Edge 2020

Vlada [557]3 years ago
4 0

Answer:

It is A

Step-by-step explanation:

Got it right on the test :)

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How do you solve 3x+7=x
vredina [299]
3x + 7 = x

First, subtract 3x from both sides. / Your problem should look like: 7 = x - 3x
Second, simplify x - 3x to -2x. / Your problem should look like: 7 = -2x
Third, divide both sides by -2. / Your problem should look like: \frac{7}{-2} = x
Fourth, simplify \frac{7}{-2} to -\frac{7}{2} / Your problem should look like: - \frac{7}{2} = x
Fifth, switch sides. / Your problem should look like: x = -\frac{7}{2}

Answer as fraction: -\frac{7}{2}
Answer as decimal: -3.5


8 0
3 years ago
Read 2 more answers
1....1/4 y + 1 1/2 + 2-1 3/4 y -12<br><br> 2....5=1/5x-3<br><br> 3....1/2 h + 1 from 3/4 h +4
Tanya [424]
1)  (-1 1/2)(y)-8 1/2
2)   x=40

 
7 0
3 years ago
What is the area of this triangle?
Lapatulllka [165]
Area is 1/2•b•h so 25
7 0
3 years ago
Three times each day, a quality engineer samples a component from a recently manufactured batch and tests it. Each part is class
Tresset [83]

Answer:

Step-by-step explanation:

Hello!

Three samples of components manufactured are taken per day. They are classified as:

D: "Conforming (suitable for its use)"

E: "Downgraded (unsuitable for the intended purpose but usable for another purpose)"

F: "Scrap (not usable)"

This classification includes the three events that may occur in your sample space S. The experiment consists in recording the categories of the three parts tested in a day.

a. List the 27 outcomes in the sample space.

The possible outcomes in the space sample are the combinations of the three events. To avoid using the same letters as in the following questions I've named the evets as D, E, and F

S={DDD, DED, DFD, DEF, DFE, DEE, DFF, DDE, DDF , EDE, EEE, EFE, EED, EEF, EDF, EFD, EDD, EFF , FDF, FEF, FFF, FFE, FFD, FDE, FED, FDD, FEE}

b. Let A be the event that all the parts fall into the same category. List the outcomes in A.

A: "All the parts fall into the same category"

You have three possible outcomes for this event, that the three compounds are conforming, "DDD", that the three are unconforming, "EEE", or that the three compounds are scrap, "FFF". There are only three possible outcomes for this event.

S={DDD, EEE, FFF}

c. Let B be the event that there is one part in each category. List the outcomes in B.

B: "There is a part in each category"

This means, for example, The first one is conforming "D", the second one is unconforming "E" and the third one is scrap "F", then the first one may be unconforming "E", the second one is conforming "D" and the thirds one is scrap "F", and so on, you have 6 possible outcomes for this event:

S={DEF, DFE, EDF, EFD, FDE, FED}

d. Let C be the event that at least two parts are conforming. List the outcomes in C.

C: "At least two parts are conforming"

For this event, you can have two of the compounds to be considered conforming or the three of them.

S={DDD, DED, DFD, DDE, DDF , EDD, FDD}

A total of 7 combinations fit this event.

I hope you have a SUPER day!

6 0
3 years ago
Which of the following graphs would represent the solution set for y &gt; 4/5 x – 1?
Keith_Richards [23]

It's this graph. You didn't give me any options in the question.

6 0
3 years ago
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