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12345 [234]
3 years ago
10

In Lixue’s garden, the green pepper plants grew 5 inches in 34 month. At this rate, how many feet can they grow in one month? (L

et 1 month = 4 weeks)
Mathematics
1 answer:
beks73 [17]3 years ago
5 0

Answer:

<h2>0.15 inches per month</h2>

Step-by-step explanation:

step one:

This problem is focused on the growth rate of a plant.

given data

the plants grow 5 inches in 34 months

and also that 1 month= 4 weeks

step two:

We can still say that

if 34 months see a growth of 5 inches

then 1 months will be X inches

cross multiply we have

X= 5/32 inches

step three:

converting this number to decimal we have

X= 0.15 inches per month

Therefore the growth rate would be

0.15 inches per month

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Answer:

B

Step-by-step explanation:

Since its changing the y, we now it has to be outside the x. So its not A or D. Since it moves up, its a plus. This means its not c, so it has to be B.

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3 years ago
What is the theoretical probability of rolling anything other than a two on a fair six sided die?
mrs_skeptik [129]

Answer:

5/6 probability

Step-by-step explanation:

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2 years ago
Order the numbers from least to greatest. 3 63/80 , 3 1/5 , 3 11/20
gregori [183]

Let's compare apples to apples and oranges to oranges: convert each given proper fraction into its decimal counterpart:

3 63/80 => 3 .788 approx.

3 1/5 => 3.2

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It's now an easy matter to arrange these numbers from least to greatest:

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3 years ago
Please help explain the steps
Gennadij [26K]

Step-by-step explanation:

3a^2+24a+45=0

×3/3( first ×3)

9a^2+24(3a)+135=0

(3a+15)(3a+9)=0

now /3

3(a+5)(a+3)

a=-5✓

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3 0
3 years ago
A researcher tests five individuals who have seen paid political ads about a particular issue. These individuals take a multiple
devlian [24]

Answer:

t=\frac{46-40}{\frac{5.148}{\sqrt{5}}}=2.606    

The degrees of freedom are given by:

df=n-1=5-1=4  

The p value wuld be given by:

p_v =2*P(t_{(4)}>2.606)=0.060  

For this case the p value is higher than the significance level so then we can conclude that the true mean is not significantly different from 40

The distribution with the critical values are in the figure attached

Step-by-step explanation:

Information given

48, 41, 40, 51, and 50

The sample mean and deviation can be calculated with these formulas:

\bar X= \frac{\sum_{i=1}^n X_i}{n}

s =\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

\bar X=46 represent the mean height for the sample  

s=5.148 represent the sample standard deviation

n=5 sample size  

\mu_o =40 represent the value that we want to test

\alpha=0.05 represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test

Hypothesis to test

We want to test if the true mean for this case is equal to 40, the system of hypothesis would be:  

Null hypothesis:\mu = 40  

Alternative hypothesis:\mu \neq 40  

The statistic is given by:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

Replacing we got:

t=\frac{46-40}{\frac{5.148}{\sqrt{5}}}=2.606    

The degrees of freedom are given by:

df=n-1=5-1=4  

The p value wuld be given by:

p_v =2*P(t_{(4)}>2.606)=0.060  

For this case the p value is higher than the significance level so then we can conclude that the true mean is not significantly different from 40

The distribution with the critical values are in the figure attached

6 0
3 years ago
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