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Luba_88 [7]
3 years ago
12

Part c and d plzzzzzzzzzz

Mathematics
1 answer:
SVEN [57.7K]3 years ago
5 0
L-2.90=J
How much does Laura earn?
I can help you with D once I know, unless we don't know what she earns. In which case, I helped with C, at least.
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A bag has yellow, red, green, blue, black, and white marbles. There are 5 of each color in the bag. What fraction of the marbles
Ahat [919]

Answer:

2/3

Step-by-step explanation:

Have a great day

8 0
3 years ago
1. To go bowling, it costs $2.00 to rent shoes and $3.50 per game. The function t(x) = 3.5x + 2 is used to find the total cost,
borishaifa [10]

Answer:

a. $5.5      b. $19.5

Step-by-step explanation:

t(x)=3.5x+2

x = amount of games

a. t(1)=3.5(1)+2

t(1)=3.5+2

t(1)=5.5

b. t(5)=3.5(5)+2

t(5)=17.5+2

t(5)=19.5

4 0
3 years ago
Draw a rhombus of side 3 cm long and a square of side 3 cm long
pochemuha

Answer: i will tell you some other day

Step-by-step explanation:

6 0
3 years ago
8x+x^2-2y-64+y^2=0 standard form with explanation
xz_007 [3.2K]
X² + 8x +y² - 2y -64 =0
We see that the equation has x² and y² . Also we see that coefficients in front of x² and y² are equal. So this is an equation of the circle.
(x² + 8x) +(y² - 2y) -64 =0
(x² + 8x) +(y² - 2y) = 64
We need to complete square for x and y groups, that means it should be written in form (a+b)² or (a-b)².
Expressions in parenthesis we will write as a²+/-2ab+b², to write it after as (a+/-b)², because  a²+/-2ab+b² = (a+/-b)²

(x² + 2*4x) +(y² - 2*1y) = 64
(x² + 2*4x+4²) +(y² - 2*1y+1²) = 64+4²+1²
(x+4)² + (y-1)²= 81 Sometimes this is called a standard form of the circle.
(x+4)² + (y-1)²= 9² Sometimes it is required to write like this.

And if you are studying circles,ellipses  and hyperbolas, the standard form should look like
\frac{(x+4)^{2}}{9^{2}} + \frac{(y-1)^{2}}{9^{2}} =1






8 0
3 years ago
Can someone help me please!!!
Andre45 [30]

Answer: 3

<u>Explanation:</u>

Since we want the least number of integers, divide by the largest integer (9).

2018 ÷ 9 = 224 remainder 2

So, N = 2999...999 <em>(there are 224 of the 9's) </em>

Thus, N + 1 = 2999...999 + 1 <em>(there are 224 of the 9's) </em>

<em>                   </em>= 3000...000     <em>(there are 224 of the 0's) </em>

The sum of the digits is: 3 + 0 + ... + 0  <em>(there are 224 of the 0's) </em>

                                      = 3

6 0
3 years ago
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