There are 5 dimes and 13 nickels
We have
f(x)=<span>−x</span>²<span>+ 5x + 6
g(x)=</span><span>3x − 2
we know that
f(x)=g(x)
the solution is the intersection both graphs
using a graph tool
see the attached figure
the solution are the points(4,10)and(-2,-8)</span>
Answer:
The number is 3000
Step-by-step explanation:
Is means equals
24 = 4/5 % *n
Lets change the percent to a decimal. To change percent, we move the decimal to places to the left.
4/5= .8
4/5 % = .8% = .008
24 = .008 *n
Divide each side by .008
24/.008 = .008n/.008
3000 = n
Amanda needs to pay 1440 cedis for purchasing 8 cakes on discounted price.
<h3>
What is Cost Price?</h3>
Cost price is the amount we pay to buy an item at which it is available.
Here,
Selling price of a cake = 200 cedis
Discount because of sale = 10% on each unit.
(Only if 4 cakes purchased at a time)
Amanda purchased 8 cakes
So, Amanda need to pay only 90 percent of the total amount.
Total cost price of 8 cakes for Amanda = (200 X 90%) X 8
= 180 X 8
= 1440
Thus, Amanda needs to pay 1440 cedis for purchasing 8 cakes on discounted price.
Learn more about Cost Price from:
brainly.com/question/11027396
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Let <em>a</em> and <em>b</em> be the zeroes of <em>x</em>² + <em>kx</em> + 12 such that |<em>a</em> - <em>b</em>| = 1.
By the factor theorem, we can write the quadratic in terms of its zeroes as
<em>x</em>² + <em>kx</em> + 12 = (<em>x</em> - <em>a</em>) (<em>x</em> - <em>b</em>)
Expand the right side and equate the coefficients:
<em>x</em>² + <em>kx</em> + 12 = <em>x</em>² - (<em>a</em> + <em>b</em>) <em>x</em> + <em>ab</em>
Then
<em>a</em> + <em>b</em> = -<em>k</em>
<em>ab</em> = 12
The condition that |<em>a</em> - <em>b</em>| = 1 has two cases, so without loss of generality assume <em>a</em> > <em>b</em>, so that |<em>a</em> - <em>b</em>| = <em>a</em> - <em>b</em>.
Then if <em>a</em> - <em>b</em> = 1, we get <em>b</em> = <em>a</em> - 1. Substitute this into the equations above and solve for <em>k</em> :
<em>a</em> + (<em>a</em> - 1) = -<em>k</em> → 2<em>a</em> = 1 - <em>k</em> → <em>a</em> = (1 - <em>k</em>)/2
<em>a</em> (<em>a</em> - 1) = 12 → (1 - <em>k</em>)/2 • ((1 - <em>k</em>)/2 - 1) = 12
→ (1 - <em>k</em>)²/4 - (1 - <em>k</em>)/2 = 12
→ (1 - <em>k</em>)² - 2 (1 - <em>k</em>) = 48
→ (1 - 2<em>k</em> + <em>k</em>²) - 2 (1 - <em>k</em>) = 48
→ <em>k</em>² - 1 = 48
→ <em>k</em>² = 49
→ <em>k</em> = ± √(49) = ±7
