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sukhopar [10]
3 years ago
13

I have no idea how to work this one

Mathematics
1 answer:
kolbaska11 [484]3 years ago
4 0
I am pretty sure it's 4
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What is the answer to this somebody!!!
Mila [183]

second one 12 5 because as you can see if you do the math divide it you get B

8 0
3 years ago
Alice bought a (k) kg of pork and (i) kg of chicken. how many kg of meat did alice buy??
n200080 [17]

Answer:

(k)kg+(l)kg=kg

Step-by-step explanation:

I just looked at letters. it's definitely wrong but I typed something so I could get points and get my answers. idc tbh but good luck ig

8 0
3 years ago
The number of bacteria after t hours is given by N(t)=250 e^0.15t a) Find the initial number of bacteria and the rate of growth
Art [367]

Answer:

a) N_0=250\; k=0.15

b) 334,858 bacteria

c) 4.67 hours

d) 2 hours

Step-by-step explanation:

a) Initial number of bacteria is the coefficient, that is, 250. And the growth rate is the coefficient besides “t”: 0.15. It’s rate of growth because of its positive sign; when it’s negative, it’s taken as rate of decay.

Another way to see that is the following:

Initial number of bacteria is N(0), which implies t=0. And N(0)=N_0. The process is:

N(t)=250 e^{0.15t}\\N(0)=250 e^{0.15(0)}\\ N_0=250e^{0}\\N_0=250\cdot1\\ N_0=250

b) After 2 days means t=48. So, we just replace and operate:

N(t)=250 e^{0.15t}\\N(48)=250 e^{0.15(48)}\\ N(48)=250e^{7.2}\\N(48)=334,858\;\text{bacteria}

c) N(t_1)=4000; \;t_1=?

N(t)=250 e^{0.15t}\\4000=250 e^{0.15t_1}\\ \dfrac{4000}{250}= e^{0.15t_1}\\16= e^{0.15t_1}\\ \ln{16}= \ln{e^{0.15t_1}} \\  \ln{16}=0.15t_1 \\ \dfrac{\ln{16}}{0.15}=t_1=4.67\approx 5\;h

d) t_2=?\; (N_0→3N_0 \Longrightarrow 250 → 3\cdot250 =750)

N(t)=250 e^{0.15t}\\ 750=250 e^{0.15t_2} \\ \ln{3} =\ln{e^{0.15t_2}}\\ t_2=\dfrac{\ln{3}}{0.15} = 2.99 \approx 3\;h

6 0
3 years ago
Find the interquartile range (IQR) of the data in the box plot below.<br><br> PLZ ASAP PLZ ASAP
Liono4ka [1.6K]

Answer:

3

Step-by-step explanation:

To find the IQR, use this formula:

Quartile 3 – Quartile 1

this will get you the IQR of a box and whisker plot :)

(pls mark brainliest)

7 0
4 years ago
1.3/4=0.975/3 determine whether the proportion is true or false
user100 [1]

Answer:

The proportion is true.

Step-by-step explanation:

By using the formula below, you can test the correctness of any proportion.

\frac{a}{b}=\frac{c}{d}

ad=bc

By plugging in the given numbers, you can test the proportion.

\frac{1.3}{4} =\frac{0.975}{3}

1.3(3)=4(0.975)

3.9=3.9

Thus, the proportion is correct.

5 0
4 years ago
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