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Aneli [31]
3 years ago
8

Estimate the value of 7.39/0.06=

Mathematics
2 answers:
ahrayia [7]3 years ago
6 0
The answer is 123 one hundred and twenty three
son4ous [18]3 years ago
5 0
The answeris 123.166666667 but rounds to 123.17

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for a stem competition julienne constructed a model rocket the rocket can reach an average height of 545 ft. Find the difference
zhenek [66]
We have the following table:
 545-534.2 = 10.8
 545-556.4 = -11.4
 545-554.0 = -9
 545-535.3 = 9.7
 write them as a positive and negative rational numbers
 positive:
 9.7 = 9 7/10
 10.8 = 10 4/5
 negative:
 -11.4 = -11 2/5
 -9 = -9
 the differences from least to greatest
 -11 2/5
 -9
 9 7/10
 10 4/5
8 0
3 years ago
The difference of 7 and the product of 4 and a is 11
BlackZzzverrR [31]
Product of 4 and a number translates to 4x because the word product means multiplication.
We then need to subtract one from that which would be 4x - 1.
The word is translates to "equals" so 4x - 1 = 11 is the translation of the whole problem.

Now solve that equation.
4x - 1 = 11
1st add +1 +1
2nd simplify 4x = 12
3rd divide. 4 4
x = 3
3 0
2 years ago
Read 2 more answers
in the school library 52% of the books are paperback if there are 2650 books in library how many of them are not paperback to th
wlad13 [49]

i will use proportions for this.

 x          52

------- = --------

2650    100

Cross multiply and u get 1378.

Hope it helps. :)

3 0
3 years ago
Find the volume of a box 24 in. x 20 in x 23 in.
kaheart [24]
<span>The definition for discovering the volume of a box is when the person takes the length, the width, and the height of the box. And because we have those values here, there is no math that is necessary to do other than multiplying the numbers together and creating a new unit of inches cubed. The answer is 11040 inches cubed.</span>
8 0
3 years ago
If a radioactive isotope has a half-life of 6 hours and 12 milligrams is initially present, how much will
Serhud [2]

Answer:0.75 milligrams will  be present in 24 hours

Step-by-step explanation:

Step 1

The formula for radioactive decay can be written as

N(t)=No (1/2)^(t/t 1/2)

where

No= The amount of the radioactive substance at time=0=milligrams

t 1/2= the half-life= 6 hours

t=24 hours

N(t) = the amount at time t

Step 2--- Solving

N(t)=No (1/2)^(t/t 1/2)

=N(t)=12 x ( 1/2) ^ (24/6)

= 12 x (1/2) ^4

= 12 x 0.0625

= 0.75 milligrams

3 0
3 years ago
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