Rice at the local market is being sold for $0.80 per pound. How much will a 3.5 pound bag of rice cost?

A travel agency has 2,106 people registered for a trip. Each tour bus can seat 54 people.

mariarad [96]

Answer:

39 buses

Step-by-step explanation:

2,106 ÷ 54 = 39

8 0

3 years ago

I'll give brainliest

Tpy6a [65]

Given:

$\angle a$ and $\angle b$ are complementary angles.

$\angle a=32^\circ$

To find:

The measure of $\angle b$ .

Solution:

According to the definition of the complimentary angles, the sum of two complementary angles is always 90 degree.

It is given that, $\angle a$ and $\angle b$ are complementary angles. So,

$\angle a+\angle b=90^\circ$

$32^\circ+\angle b=90^\circ$

$\angle b=90^\circ-32^\circ$

$\angle b=58^\circ$

Therefore, the measure of $\angle b$ is 58°.

3 0

3 years ago

What is (0.2 + -5) x (4.1) ?

nevsk [136]

Answer:

-19.68

Step-by-step explanation:

(0.2 + (-5) × (4.1)

-4.8 × (4.1)

-19.68

6 0

3 years ago

Read 2 more answers

(A) A small business ships homemade candies to anywhere in the world. Suppose a random sample of 16 orders is selected and each

Leviafan [203]

Following are the solution parts for the given question:

For question A:

$\to (n) = 16$

$\to (\bar{X}) = 410$

$\to (\sigma) = 40$

In the given question, we calculate $90\%$ of the confidence interval for the mean weight of shipped homemade candies that can be calculated as follows:

$\to \bar{X} \pm t_{\frac{\alpha}{2}} \times \frac{S}{\sqrt{n}}$

$\to C.I= 0.90\\\\\to (\alpha) = 1 - 0.90 = 0.10\\\\ \to \frac{\alpha}{2} = \frac{0.10}{2} = 0.05\\\\ \to (df) = n-1 = 16-1 = 15\\\\$

Using the t table we calculate $t_{ \frac{\alpha}{2}} = 1.753$ When $90\%$ of the confidence interval:

$\to 410 \pm 1.753 \times \frac{40}{\sqrt{16}}\\\\ \to 410 \pm 17.53\\\\ \to392.47 < \mu < 427.53$

So $90\%$ confidence interval for the mean weight of shipped homemade candies is between $392.47\ \ and\ \ 427.53$ .

For question B:

$\to (n) = 500$

$\to (X) = 155$

$\to (p') = \frac{X}{n} = \frac{155}{500} = 0.31$

Here we need to calculate $90\%$ confidence interval for the true proportion of all college students who own a car which can be calculated as

$\to p' \pm Z_{\frac{\alpha}{2}} \times \sqrt{\frac{p'(1-p')}{n}}$

$\to C.I= 0.90$

$\to (\alpha) = 0.10$

$\to \frac{\alpha}{2} = 0.05$

Using the Z-table we found $Z_{\frac{\alpha}{2}} = 1.645$

therefore $90\%$ the confidence interval for the genuine proportion of college students who possess a car is

$\to 0.31 \pm 1.645\times \sqrt{\frac{0.31\times (1-0.31)}{500}}\\\\ \to 0.31 \pm 0.034\\\\ \to 0.276 < p < 0.344$

So $90\%$ the confidence interval for the genuine proportion of college students who possess a car is between $0.28 \ and\ 0.34.$

For question C:

In question A, We are $90\%$ certain that the weight of supplied homemade candies is between 392.47 grams and 427.53 grams.
In question B, We are $90\%$ positive that the true percentage of college students who possess a car is between 0.28 and 0.34.

Learn more about confidence intervals:

brainly.in/question/16329412

7 0

3 years ago

3(x - 6) + 6 = 5x - 6. what is the solution<br>

4vir4ik [10]

Answer:

x=-3

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

3(x−6)+6=5x−6

(3)(x)+(3)(−6)+6=5x+−6(Distribute)

3x+−18+6=5x+−6

(3x)+(−18+6)=5x−6(Combine Like Terms)

3x+−12=5x−6

3x−12=5x−6

Step 2: Subtract 5x from both sides.

3x−12−5x=5x−6−5x

−2x−12=−6

Step 3: Add 12 to both sides.

−2x−12+12=−6+12

−2x=6

Step 4: Divide both sides by -2.

−2x

−2

=

6

−2

x=−3

7 0

3 years ago

Read 2 more answers

Rice at the local market is being sold for $0.80 per pound. How much will a 3.5 pound bag of rice cost? ​

Rice at the local market is being sold for $0.80 per pound. How much will a 3.5 pound bag of rice cost?