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statuscvo [17]
4 years ago
14

3(x - 6) + 6 = 5x - 6. what is the solution​

Mathematics
2 answers:
inn [45]4 years ago
8 0

Answer: x = -3

Step-by-step explanation:

1. Distribute the 3 into the parenthesis

     3x - 18 + 6 = 5x - 6

2. Combine like terms (on the left side of the equation

    3x - 12 = 5x - 6

3. Add 6 to both sides to get rid of the -6 on the right side

    3x - 6 = 5x

4. Subtract 3x from both sides to get rid of the 3x from the left side

    -6 = 2x

5. Divide both sides by 2

    -3 = x    

4vir4ik [10]4 years ago
7 0

Answer:

x=-3

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

3(x−6)+6=5x−6

(3)(x)+(3)(−6)+6=5x+−6(Distribute)

3x+−18+6=5x+−6

(3x)+(−18+6)=5x−6(Combine Like Terms)

3x+−12=5x−6

3x−12=5x−6

Step 2: Subtract 5x from both sides.

3x−12−5x=5x−6−5x

−2x−12=−6

Step 3: Add 12 to both sides.

−2x−12+12=−6+12

−2x=6

Step 4: Divide both sides by -2.

−2x

−2

=

6

−2

x=−3

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A semicircle measures 180°

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Step-by-step explanation:

7 0
3 years ago
HELP ME PLEASE!!! What is the value of y for the parallelogram shown A. 66 B. 60 C. 22 D. 38
Nesterboy [21]

Answer:

<h2><em>2</em><em>2</em></h2>

<em>Option </em><em>C</em><em> </em><em>is</em><em> </em><em>the</em><em> </em><em>correct</em><em> </em><em>option</em><em>.</em>

<em>Solu</em><em>tion</em><em>,</em>

<em>3y = 66</em>

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<em>or  \: 3 \times y = 66 \\ or \: y =  \frac{66}{3}  \\ y = 22</em>

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5 0
3 years ago
The center of a circle lies on the line y = 4x + 1 and is tangent to the x-axis at (−3,0) . What is the equation of the circle i
Hunter-Best [27]

Answer:

(x+3)^2+(y+11)^2=121

Step-by-step explanation:

Consider a sketch of the problem as shown in the picture, where:

  • Blue line is given by y = 4x + 1.
  • Point B is the center of the circle.
  • Point A is (-3, 0).

Since the center of the circle lies on the line y = 4x +1 and is tangent to the x-axis at point A, then its radius BA is perpendicular to the x-axis. To find the coordinates of point B, we must replace x = -3 into the blue line equation: y = 4x(-3) + 1 = -11.

So, we know that the center of the circle is at B=(-3, -11). And furthermore, the radius BA is of length r=11.

Since the <em>general equation of the circle</em> of radius lenght r centered at (h, k) is given by

(x-h)^2+(y-k)^2=r^2

then with h = -3, k = -11 and r= 11, the equation of our circle is

(x+3)^2+(y+11)^2=121

5 0
3 years ago
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Len [333]

Answer:

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