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Contact [7]
3 years ago
12

I need assistance agane

Mathematics
1 answer:
amid [387]3 years ago
4 0
All you have to do is divide the answer by the height it gives you to find the length
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A bin contains 25 light bulbs, 5 of which are in good condition and will function for at least 30 days, 10 of which are partiall
Ira Lisetskai [31]

Answer:

The probability that it will still be working after one week is \frac{1}{5}

Step-by-step explanation:

Given :

Total number of bulbs = 25

Number of bulbs which are good condition and will function for at least 30 days = 5

Number of bulbs which are partially defective and will fail in their second day of use = 10

Number of bulbs which are totally defective and will not light up = 10

To find : What is the probability that it will still be working after one week?

Solution :

First condition is a randomly chosen bulb initially lights,

i.e. Either it is in good condition and partially defective.

Second condition is it will still be working after one week,

i.e. Bulbs which are good condition and will function for at least 30 days

So, favorable outcome is 5

The probability that it will still be working after one week is given by,

\text{Probability}=\frac{\text{Favorable outcome}}{\text{Total number of outcome}}

\text{Probability}=\frac{5}{25}

\text{Probability}=\frac{1}{5}

5 0
3 years ago
Amy ate 2 1/2 cookies after lunch ,and 1 2/5 cookies after dinner.How many cookies did she eat altogether
Mrac [35]
2 1/2 + 1 2/5 = 3 9/10...Please give brainliest....
3 0
3 years ago
Read 2 more answers
Ken predicts that the average temperature will be −5°C in December. If he predicts the temperature will rise 6°C in January and
ipn [44]

Answer:

The equations [(-5) + (-3)] + 6 = -2 and [6 + (-5)] + (-3) = -2  he can use to find the sum of the temperatures for those months ⇒ 3rd , 5th

Step-by-step explanation:

i took the assignment

7 0
3 years ago
See image attached below keeeeeeeeeeeeeeeeeeeed
emmasim [6.3K]

Answer:

.13%

68.26%

2.28%

47.72%

49.87%

34.13%

Step-by-step explanation:

1.) standardize by subtracting the mean and dividng by the standard deviation

(625-1000)/125= -3

go to a ztable to get .0013 or (1-.9987)

this is equal to .13%

2.)

875<x<1125

standardize both seperately and subtract them

(875-1000)/125= -1  whose probability is .1587 (or 1-.8413)

(1125-1000)/125= 1  whose probability is .8413

.8413-.1587= 68.26%

3.)

Find the probability that someone paid less than 1250 and take its compliment

(1250-1000)/125= 2 which has a probability of .9772

take its compliment (1-.9772)= .0228= 2.28%

4.)

Same process as question 2

(750-1000)/125= -2 which has a probability of (1-.9772) = .0228

(1000-1000)/125= 0 which has a probability of .5

.5-.0228= .4772= 47.72%

5.) same deal as the previous question

(625-1000)/125= -3 which has a probability of (1-.9987)= .0013

(1000-1000)/125= 0 which has a probability of .5

.5-.0013= .4987= 49.87%

6.)same deal the previous question

(875-1000)/125= -1 which has a probability of (1-.8413)=.1587

(1000-1000)/125= 0 which has a probability of .5

.5-.1587= .3413= 34.13%

4 0
2 years ago
The range of the function f(k) = k2 + 2k + 1 is {25, 64}. What is the function’s domain?
MAXImum [283]
<span>f(k) = k2 + 2k + 1 = (k+1)^2
The range is what the function gives to you f(k)=25=5^2 or (-5)^2
f(k)=64=8^2 or (-8)^2

You need to find the k values for these boundary values to find the domain. 
Good luck :)</span>
7 0
3 years ago
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