The polynomial
may have solutions which are the divisors of -20, therefore -20 has the following divisors:
.
If x=1, then
,
if x=-1, then
,
if x=2, then
, then x=2 is a solution and you have the first factor (x-2).
If x=-2, then
, then x=-2 is a solution, so you have the second factor (x+2).
Since x-2 and x+2 are two factors of
, then the polynomial
is a divisor of
and dividing the polynomial
by
you obtain
.
<h3>hello!</h3>
let's evaluate this expression
Multiply:
Final Step:-
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<h3>note:-</h3>
Hope everything is clear; if you need any explanation/clarification, kindly let me know, and I'll comment and/or edit my answer :)
Answer:
None of these.
Step-by-step explanation:
Let's assume we are trying to figure out if (x-6) is a factor. We got the quotient (x^2+6) and the remainder 13 according to the problem. So we know (x-6) is not a factor because the remainder wasn't zero.
Let's assume we are trying to figure out if (x^2+6) is a factor. The quotient is (x-6) and the remainder is 13 according to the problem. So we know (x^2+6) is not a factor because the remainder wasn't zero.
In order for 13 to be a factor of P, all the terms of P must be divisible by 13. That just means you can reduce it to a form that is not a fraction.
If we look at the first term x^3 and we divide it by 13 we get 
we cannot reduce it so it is not a fraction so 13 is not a factor of P
None of these is the right option.
The answer is the second choice. Hope that was helpful
