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MAVERICK [17]
3 years ago
14

Can I have some help

Mathematics
1 answer:
TiliK225 [7]3 years ago
8 0
What do you need help with

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How do you find the legs of a right triangle when only given the hypotenuse?
tangare [24]

Answer:

We know that a^2+b^2=c^2. The 45° angle lets us know that y=x (45+45+90=180), so the problem is y^2+x^2=4sqrt of 2

4 \sqrt{2}  =  \sqrt{32 }  \\    \sqrt{32} ^{2}  = 32

So you get y^2+x^2=32, and from there, since we know x and y are equal, you can just divide 32 by 2 then take the square root of that, so the answer should be <em><u>4</u></em><em><u> </u></em><em><u>for</u></em><em><u> </u></em><em><u>both</u></em><em><u> </u></em><em><u>x</u></em><em><u> </u></em><em><u>and</u></em><em><u> </u></em><em><u>y</u></em>

Step-by-step explanation:

let me know if I'm wrong lol

6 0
2 years ago
Need help to solve please??<br> Need to proof
inysia [295]

Answer:

Step-by-step explanation:

#   Statement   Reasoning

1). KJ║ML    Given

2). ∠KLM ≅ ∠LKJ   Alternate interior angles

3). KL ≅ LK  Reflexive property

4). ΔKJL ≅ ΔLMK  SAS congruence postulate

8 0
2 years ago
A particular brand of tires claims that its deluxe tire averages at least 50,000 miles before it needs to be replaced. From past
Vadim26 [7]

Answer:

We conclude that deluxe tire averages less than 50,000 miles before it needs to be replaced which means that the claim is not supported.

Step-by-step explanation:

We are given that a particular brand of tires claims that its deluxe tire averages at least 50,000 miles before it needs to be replaced. From past studies of this tire, the standard deviation is known to be 8000.

From the 28 tires surveyed, the mean lifespan was 46,500 miles with a standard deviation of 9800 miles.

<u><em>Let </em></u>\mu<u><em> = average miles for deluxe tires</em></u>

So, Null Hypothesis, H_0 : \mu \geq 50,000 miles   {means that deluxe tire averages at least 50,000 miles before it needs to be replaced}

Alternate Hypothesis, H_A : \mu < 50,000 miles    {means that deluxe tire averages less than 50,000 miles before it needs to be replaced}

The test statistics that will be used here is <u>One-sample z test statistics</u> as we know about population standard deviation;

                                  T.S.  = \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \bar X = sample mean lifespan = 46,500 miles

            \sigma = population standard deviation = 8000 miles

            n = sample of tires = 28

So, <u><em>test statistics</em></u>  =  \frac{46,500-50,000}{\frac{8000}{\sqrt{28} } }

                               =  -2.315

The value of the test statistics is -2.315.

Now at 5% significance level, the z table gives critical value of -1.6449 for left-tailed test. Since our test statistics is less than the critical value of z as -2.315 < -1.6449, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that deluxe tire averages less than 50,000 miles before it needs to be replaced which means that the claim is not supported.

4 0
3 years ago
Verify sin(360° - 0) = -sin0​
zaharov [31]

Answer:

see explanation

Step-by-step explanation:

Using the Addition formula for sine

sin(x ± y) = sinxcosy ± cosxsiny

Consider the left side

sin(360 - Θ ), then

= sin360°cosΘ - cos360°sinΘ

= 0 × cosΘ - 1 × sinΘ

= 0 - sinΘ = - sinΘ → verified

6 0
3 years ago
Read 2 more answers
A bag contains 11 tiles, one for each of the letters in the word BLUEBERRIES. You randomly choose a tile.
wel
2/11

there’s 2 R’s and 11 total so

possible outcomes/ overall outcomes
7 0
3 years ago
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