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BlackZzzverrR [31]
3 years ago
15

Which number rounds to the nearest 300,00when rounding to the nearest thousand

Mathematics
1 answer:
stealth61 [152]3 years ago
5 0
What are the numbers
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Find the missing side length of the right triangle.
Tomtit [17]
This is just some pythagorean theorem, or a^2 + b^2 = c^2. We have a and b, which is 9 and 12, and we need to find c. To find c, we need to first square those, giving u 81 and 144. Now, we need to add them, giving us 225, meaning c^2 = 225. However, we need to find c on its own, so we have to find the square root of 225. That would be 15.
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Lucinda leaves money in her savings account for 8 years. She started with $800 and earned 3.5% interest compound annually. How m
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3 years ago
I really need help with this!!! someone help please
Minchanka [31]

Answer:

156 in squared

Step-by-step explanation:

So the formulas will be stated below

Parallelogram Area= 1/2h(b1+b2)

Square Area= Bh

So first do

(4)(12+6)

(4)(18)

No need to half it bc there's the same shape at the bottom

72+18+30+36

6(3)

3x5(2)

12(3)

5 0
3 years ago
EXPERTS PLEASE HELP!!!!!!!!!!!!!!
Arturiano [62]

Answer:

1. D

2. x=65

Step-by-step explanation:

Hi!

Your answer is D because 78 is 120% of x

120% in decimal point is 1.2.

So it's 1.2x is the same as 120% of x

For question 8:

1.2x=78

Isolate x by divide 1.2 on both sides

78/1.2=65

7 0
3 years ago
Why is the equation y-y1=m(x-x1) called the point-slope form?
MatroZZZ [7]

Answer:

The equation of the line with slope m = 2 and passing through the point (1, 1) will be:

y = 2x

Step-by-step explanation:

We know that the point-slope form of the line equation is

y-y_1=m\left(x-x_1\right)

where

  • m is the slope of the line
  • (x₁, y₁) is the point

The formula y-y_1=m\left(x-x_1\right) is termed as the point-slope form of the line equation because if we know one point on a certain line and the slope of that line, then we can easily get the line equation with this formula and, hence, determine all other points on the line.

For example, if we are given the point (1, 1) and slope m = 2

Then substituting the values m = 2 and the point (1, 2)

y-y_1=m\left(x-x_1\right)

y - 2 = 2(x-1)

y - 2 = 2x-2

y = 2x-2+2

y = 2x

Therefore, the equation of the line with slope m = 2 and passing through the point (1, 1) will be:

y = 2x

5 0
2 years ago
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