Answer:
A or B or C or D, one of those
Answer:
<em>Numbers: 6 and -2</em>
Step-by-step explanation:
<u>Equations</u>
This question can be solved by inspection. It's just a matter of factoring 12 into two factors that sum 4. Both numbers must be of different signs and they are 6 and -2. Their sum is indeed 6-2=4 and their product is 6*(-2)=-12.
However, we'll solve it by the use of equations. Let's call x and y to the numbers. They must comply:
![x+y=4\qquad\qquad [1]](https://tex.z-dn.net/?f=x%2By%3D4%5Cqquad%5Cqquad%20%5B1%5D)
![x.y=-12\qquad\qquad [2]](https://tex.z-dn.net/?f=x.y%3D-12%5Cqquad%5Cqquad%20%5B2%5D)
Solving [1] for y:

Substituting in [2]

Operating:

Rearranging:

Solving with the quadratic formula:

With a=1, b=-4, c=-12:



The solutions are:


This confirms the preliminary results.
Numbers: 6 and -2
The area is 36 units squared.
You have three ways you can solve this question.
Method 1:
Split the rhombus into two equal triangles.
You will get triangle ACD and triangle ACB.
Count the base length and height length of each triangle using the diagram.
You will get base = 6 units and height = 6 units. Plug this into the area of a triangle and then multiply it by 2.
A = bh/2 * 2
A = 6(6) / 2 * 2
A = 36 / 2 * 2
A = 18 * 2
A = 36
Method 2:
Calculate the length of DP.
The length of line segment DP is √28.8
Calculate the length of DC.
The length of line segment DC is 3√5
Put into equation A = bh.
A = bh
A = 3√5(√28.8)
A = 36
Method 3:
Calculate the length of each diagonal and put into formula A = 1/2(d1 * d2)
Diagonal DB = 12 units
Diagonal AC = 6 units
A = 1/2(d1 * d2)
A = 1/2(12 * 6)
A = 1/2(72)
A = 36
I love procrastinating my history essay for this :D
Total perimeter is 522 ft. I will guess the gym is a big rectangle.
Therefore, Perimeter of a rectangle = 2L + 2W
P= 2L+ 2W
We know 80 ft wide. so now we plug and chug the equation we came up with
P=522 ft
P=2L+ 2(80)
522=2L+ 160
L= 181
hope that helps