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3 years ago

Which of the following is the graph of the inequality y< -2x + 3?

Mathematics

1 answer:

zaharov [31]3 years ago

3 0

Answer:

look at the photo

Step-by-step explanation:

Since the inequality is already written in y=mx+b, you can easily graph the line. +3 is the y intercept, so one point would be (0,3). -2 resembles the slope, so diagonally to the left, you would go up 2 and across 1. Also, since the sign is "<" you would graph with a dotted line. Then to know which side to shade, I always use the coordinate (0,0). I plug in 0 for both x and y to see if (0,0) satisfies the inequality. In this case it does, so you would shade on the side where (0,0) is located.

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a scaled drawing of a rectangular park is 5 inches wide and 7 inches long. the actual park is 210 yards long. what is the width

VMariaS [17]

Answer:

I think the width would be 150 yd

Step-by-step explanation:

just broke down the 210 yd we had already to inches found out how much it was scaled up and did the same on the other side

6 0

2 years ago

Read 2 more answers

You're at a clothing store that dyes your clothes while you wait. You get to pick from 444 pieces of clothing (shirt, pants, soc

AlexFokin [52]

Answer:

1/12

Step-by-step explanation:

There are 4 clothing choices and 3 colors.

4x3=12

This means you have a 1 in 12 chance of getting an orange hat.

This presupposes that there are EQUAL numbers of pieces and colors. (111 of each).

4 0

2 years ago

How many liters each of a 35% acid solution and a 80% acid solution must be used to produce 60 liters of a 65% acid solution? (R

serg [7]

Solving a system of equations we will see that we need to use <u>40 liters of the 80% acid solution</u>, and the other <u>20 liters are of the 35% acid solution</u>.

<h3>How many liters of each solution do we need to use?</h3>

First, we need to define the variables:

x = liters of the 35% acid used.
y = liters of the 80% acid used.

We know that we want to produce 60 liters of 65% acid, then we have the system of equations:

x + y = 60

x*0.35 + y*0.80 = 60*0.65

(in the second equation we wrote the percentages in decimal form).

To solve this we need to isolate one of the variables in one equation and then replace it in other one, isolating x we get:

x = 60 - y

Replacing that in the other equation:

(60 - y)*0.35 + y*0.80 = 60*0.65

y*(0.80 - 0.35) = 60*(0.65 - 0.35)

y*0.45 = 60*0.30

y = 60*0.30/0.45 = 40

So we need to use <u>40 liters of the 80% acid solution</u>, and the other <u>20 liters are of the 35% acid solution</u>.

If you want to learn more about systems of equations:

brainly.com/question/13729904

#SPJ1

7 0

1 year ago

The product of four consecutive odd numbers(all four positive or all four negative)is 62985.find the two possible sets of four n

emmasim [6.3K]

Answer:

Step-by-step explanation:

Let X be the first number.

(X)*(X+2)*(X+4)*(X+6) = 62985

(X^2 + 6X)^2 + 8(X^2 + 6X) = 62985

X = 13, AND X= -19

A. X = 13

(13)(15(17)(19) = 62985

B. X = -19

(-19)(-17)(-15)(-13) = 62985

8 0

1 year ago

Which of the following is NOT a variation of a Pythagorean identity?

Ipatiy [6.2K]

The expression that is not a variation of the Pythagorean identity is the third option.

<h3>What is the Pythagorean identity?</h3>

The Pythagorean identity can be written as:

$sin^2(x) + cos^2(x) = 1$

For example, if we subtract cos^2(x) on both sides we get the second option:

$sin^2(x) = 1 - cos^2(x)$

Which is a variation.

Now, let's divide both sides by cos^2(x).

$sin^2(x)/cos^2(x) + cos^2(x)/cos^2(x) = 1/cos^2(x)\\\\tan^2(x) + 1 = sec^2(x)\\\\tan^2(x) - sec^2(x) = -1$

Notice that the third expression in the options looks like this one, but the one on the right side is positive. The above expression is in did a variation of the Pythagorean identity, then the one written in the options (with the 1 instead of the -1) is incorrect, meaning that it is not a variation of the Pythagorean identity.

Concluding, the correct option is the third one.

If you want to learn more about the Pythagorean identity, you can read:

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3 0

2 years ago