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mash [69]
3 years ago
11

Help me answer this question and explain how you got your answer please

Mathematics
1 answer:
Aleks04 [339]3 years ago
6 0
5.25+2.50 gives you 7.75 then take away to find the change from 10 dollars so 10-7.75 gives you 2.25 ^^; hope this helps 
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How do you solve this equation: -2m+3=|15+m|
Elden [556K]

Any number inside the modulus sign becomes positive. This means |15+m|=|-(15+m)|=|-15-m| and so we have,

-2m+3=|15+m| \Rightarrow \left \Big\{ {{-2m+3=15+m} \atop{-2m+3=-15-m}} \right

Solving these gives us

-2m+3=15+m \Rightarrow m=-4

-2m+3=-15-m \Rightarrow = m=18

However if we check the second solution in the original equation we obtain -2(18)+3=|15+18| \Rightarrow -33=33. This is false and so m=18 can't be a solution.

Therefore the only solution is m=-4.

(Note: I'm not sure why the second solution didn't work but when there's a modulus sign involved it always pays to check your final answers to be sure. I'll have a think about it but in case you find out before I do, I'd be interested to know in the comments.)

8 0
3 years ago
Work out the value of (2^3)^2​
aniked [119]

Answer:

2^6

64

Step-by-step explanation:

7 0
3 years ago
What is 3x+5Y=15for y
yarga [219]
Y can equal 3, if x=0. i hoped i helped. please mark my responce as brainiest.
8 0
3 years ago
How do u do b??????????
horrorfan [7]

the assumption being that the first machine is the one on the left-hand-side and the second is the one on the right-hand-side.

the input goes to the 1st machine and the output of that goes to the 2nd machine.

a)

if she uses and input of 6 on the 2nd one, the result will be 6² - 6  = 30, if we feed that to the 1st one the result will be √( 30 - 5) = √25 = 5, so, simply having the machines swap places will work to get a final output of 5.

b)

clearly we can never get an output  of -5 from a square root, however we can from the quadratic one, the 2nd machine/equation.

let's check something, we need a -5 on the 2nd, so

\bf \underset{final~out put}{\stackrel{y}{-5}}=x^2-6\implies 1=x^2\implies \sqrt{1}=x\implies 1=x

so if we use a "1" as the output on the first machine, we should be able to find out what input we need, let's do that.

\bf \underset{first~out put}{\stackrel{y}{1}}=\sqrt{x-5}\implies 1^2=x-5\implies 1=x-5\implies 6=x

so if we use an input of 6 on the first machine, we should be able to get a -5 as final output from the 2nd machine.

\bf \stackrel{first~machine}{y=\sqrt{\boxed{6}-5}}\implies y=\sqrt{1}\implies y=1 \\\\\\ \stackrel{second~machine}{y = \boxed{1}^2-6}\implies y = 1-6\implies y = -5

5 0
3 years ago
57% people ordered steak. 120 did not. how many customers were there that night?
jok3333 [9.3K]
X - number of customers

120+57\%x=x\\
120+0.57x=x\\
0.43x=120\\
x\approx297.07

There can't be a fraction of the number of people, so there must be some mistake in the question.
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4 0
2 years ago
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