5^(x+7)=(1/625)^(2x-13)
We move all terms to the left:
5^(x+7)-((1/625)^(2x-13))=0
Domain of the equation: 625)^(2x-13))!=0
x∈R
We add all the numbers together, and all the variables
5^(x+7)-((+1/625)^(2x-13))=0
We multiply all the terms by the denominator
(5^(x+7))*625)^(2x+1-13))-((=0
We add all the numbers together, and all the variables
(5^(x+7))*625)^(2x-12))-((=0
We add all the numbers together, and all the variables
(5^(x+7))*625)^(2x=0
not sure if this is right :/
Answer:
Step-by-step explanation:
Answers:
a) k=11
b) k=10
c) k=-3
d) k=4
e) k=1
I do not mind explaining
For the point (3,k) and virtually every point, 3 is the x coordinate and k is the y coordinate. Therefore, we can substitute 3 for x and solve for k (which is y).
a) 3(3)+2=11
b) 4(3)-2=10
c) 3-2(3)=3-6=-3
d) 3+4=7
e) 3-2(1)=1
first turn into an improper fraction can you divide.
Factor out the common term <span>u<span>
</span></span>