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natulia [17]
3 years ago
9

Solve the rational equation 1/n-4 - 2/n = 3/4-n

Mathematics
1 answer:
Leokris [45]3 years ago
5 0

Answer:

n=4

Step-by-step explanation:

Given equation: \[\frac{1}{n-4}-\frac{2}{n}=\frac{3}{4-n}\]

Simplifying the Left Hand Side of the equation by taking the LCM of the denominator terms:

\[\frac{n}{n*(n-4)}-\frac{2*(n-4)}{n*(n-4)}=\frac{3}{4-n}\]

=> \[\frac{n - 2*(n-4)}{n*(n-4)}=\frac{3}{4-n}\]

=> \[\frac{n - 2n + 8}{n*(n-4)}=\frac{3}{4-n}\]

=> \[\frac{8 - n}{n*(n-4)}=\frac{3}{4-n}\]

=> \[(8-n)*(4-n) =n*(n-4)*3\]

=> \[n-8 =3n\]

=> \[2n =8\]

=> n = 4

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Step-by-step explanation:

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  4x +4x +4x +4x = x(4+4+4+4) = 16x

  -7x +4 +3x = x(-7+3) +4 = -4x +4

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3 0
3 years ago
Find the quotient of these complex numbers.
stich3 [128]

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Answer:

  C.  (45+11i)/29

Step-by-step explanation:

Multiply numerator and denominator by the conjugate of the denominator.

  \dfrac{5-7i}{2-5i}=\dfrac{(5-7i)(2+5i)}{(2-5i)(2+5i)}=\dfrac{(5)(2)+(-7i)(5i) +(5)(5i)+(-7i)(2)}{2^2+5^2}\\\\=\dfrac{(10+35)+(24-14)i}{29}=\boxed{\dfrac{45}{29}+\dfrac{11}{29}i}

8 0
2 years ago
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sergeinik [125]
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4 0
3 years ago
Question<br> (X-5y/y3)-1=
Ilia_Sergeevich [38]

Answer:

x  = y^3+5y

Step-by-step explanation:

Complete question

\frac{x - 5y}{y^3} - 1=0\\

Required

Solve for x

We have:

\frac{x - 5y}{y^3} - 1=0

Collect like terms

\frac{x - 5y}{y^3} = 1

Multiply through by y^3

x - 5y = y^3

Make x the subject

x  = y^3+5y

8 0
2 years ago
The function, f(x) = –2x2 + x + 5, is in standard form. The quadratic equation is 0 = –2x2 + x + 5, where a = –2, b = 1, and c =
avanturin [10]
Given:

The function, f(x) = -2x^2 + x + 5

Quadratic equation: 0 = -2x^2 + x +5
where a = -2
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The discriminate b^2 - 4ac = 41

To solve for the zeros of the quadratic function, use this formula:

x = ( -b +-√ (b^2 - 4ac) ) / 2a

x = ( 1 + √41 ) / 4  or 1.85
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Therefore, the zeros of the quadratic equation are 1.85 and -1.35. 
4 0
3 years ago
Read 2 more answers
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