Answer:
assuming that the question says "how many games did he not attend" it would be 26
Figure is missing, so i have attached it.
Answer:
it will clear the arch because the height of the archway of the bridge 5 feet from the center is approximately 12.76 ft
Step-by-step explanation:
The standard form of equation of an ellipse is;
x²/a² + y²/b² = 1
From the figure in the image attached, we can see that the radius is; a = 52/2 = 26 ft
While the value of b = 13 ft
Thus;
x²/26² + y²/13² = 1
x²/676 + y²/169 = 1
We want to find the height of the archway of the bridge 5 feet from the center.
Thus, we will plug in 5 for x to get;
5²/676 + y²/169 = 1
(25/676) + (y²/169) = 1
Multiply through by 676 to get;
25 + 4y² = 676
4y² = 676 - 25
y² = 651/4
y² = 162.75
y = 12.76 ft
Thus height of the truck is 12 ft and so it will clear the arch because the height of the archway of the bridge 5 feet from the center is approximately 12.76 ft
Answer:
8x + 8y
Step-by-step explanation:
Simplify
Hope this helps. Have a great day. :)
-wfz
1st : Find the volume of the rectangular block:
12 × 10 × 20 = 2400 cm^3.
2nd : Find the volume of a cylinder
![\pi {r}^{2} h](https://tex.z-dn.net/?f=%5Cpi%20%20%7Br%7D%5E%7B2%7D%20h)
Where r is radius & h is height.
so:
![\pi \times 2.2 {}^{2} \times 5.0](https://tex.z-dn.net/?f=%5Cpi%20%5Ctimes%202.2%20%7B%7D%5E%7B2%7D%20%20%5Ctimes%205.0)
= 76.02654222 cm^3
Lastly, divide the volume of the rectangular block by the volume of the cylinder
2400 ÷ 76.026 = 31.5679226
You can't round it up so the answer is F) 31