Answer:
7\6
Step-by-step explanation: seven over 6
This question is incomplete, the complete question is;
A cold medicine lists 600 milligrams of acetaminophen per fluid ounce as an active ingredient. A test of 75 one-ounce samples of the medicine finds that the mean amount of acetaminophen for the sample is 593 milligrams with a standard deviation of 22 milligrams. Test the claim that the medicine does not contain the required amount of acetaminophen. Use a 0.05 significance level.
Answer:
p-value (0.0058) < given that significance level ∝ (0.05)
So we Reject the Null Hypothesis
Step-by-step explanation:
Given that;
n = 75
x" = 593
σ = 22
H₀ : μ = 600
Hₐ : μ ≠ 600
first we find our z-score;
z = (x" - μ) / σ√n
we substitute
z = (593 - 600) / (22/√75)
= -7 / 2.5403
= - 2.76
now p-value = 2P( Z ≤ z ) { two tailed)
= 2P( Z ≤ -2.76 )
from z-table { -2.76 = 0.0029)
so
p-value = 2 × 0.0029
p-value = 0.0058
given that significance level ∝ = 0.05
p-value (0.0058) < given that significance level ∝ (0.05)
So we Reject the Null Hypothesis
Answer:
Step-by-step explanation:
Given : Expression
To find : Solve this expression ?
Solution :
E denotes the power of 10,
Substitute in the expression,
Answer: 36 - 100%
43 - x %
Step-by-step explanation 36 - 100%
43 - x %
we multiply by cross -> 36 * x = 100 / 43
we should remove '100%' from new value, because we find only increase.. no new value in percent.
x + 100 = (43 * 100)/36
x = 4300/36 - 100
x = 119+ 16/36 -100
x = 19 +4/9