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dalvyx [7]
3 years ago
12

Solve for x -2x -3<5

Mathematics
2 answers:
zysi [14]3 years ago
4 0

Answer:

i think it's

x > - 8

Step-by-step explanation:

hope this helps :)

Tems11 [23]3 years ago
3 0

Answer:

Inequality form

x > - 8

Step-by-step explanation:

hope this helps

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Y-3=-3y-43 how would i solve?​
frez [133]

Answer: y−3=−3y−43

Step 1: Add 3y to both sides.

y−3+3y=−3y−43+3y

4y−3=−43

Step 2: Add 3 to both sides.

4y−3+3=−43+3

4y=−40

Step 3: Divide both sides by 4.

4y

4

=

−40

4

y=−10

Answer:

y=−10

Step-by-step explanation: brainliest:)

7 0
3 years ago
(Fill in the blank)<br> Solve the following equation.
swat32

Answer:

there is no ecuashon

Step-by-step explanation:

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3 0
3 years ago
Read 2 more answers
Maya deposits $5000 into a checking account that pays 0.75% annual interest compounded monthly. What will be the balance after 8
Nana76 [90]

~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$5000\\ r=rate\to 0.75\%\to \frac{0.75}{100}\dotfill &0.0075\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{monthly, thus twelve} \end{array}\dotfill &12\\ t=years\dotfill &8 \end{cases} \\\\\\ A=5000\left(1+\frac{0.0075}{12}\right)^{12\cdot 8}\implies A=5000(1.000625)^{96}\implies A\approx 5309.08

5 0
2 years ago
How could you put that is a mathematic form??
Vladimir [108]
Where's the picture???? I'm confusedd
7 0
2 years ago
you pick a card at random without getting the first card back you pick a second card at random what is the probability of pickin
Keith_Richards [23]

We have to calculate the probability of picking a 4 and then a 5 without replacement.

We can express this as the product of the probabilities of two events:

• The probability of picking a 4

,

• The probability of picking a 5, given that a 4 has been retired from the deck.

We have one card in the deck out of fouor cards that is a "4".

Then, the probability of picking a "4" will be:

P(4)=\frac{1}{4}

The probability of picking a "5" will be now equal to one card (the number of 5's in the deck) divided by the number of remaining cards (3 cards):

P(5|4)=\frac{1}{3}

We then calculate the probabilities of this two events happening in sequence as:

\begin{gathered} P(4,5)=P(4)\cdot P(5|4) \\ P(4,5)=\frac{1}{4}\cdot\frac{1}{3}=\frac{1}{12} \end{gathered}

Answer: 1/12

8 0
1 year ago
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