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4 years ago

Andrew is taking a multiple choice test with a total of 80 points available. Each

Mathematics

1 answer:

Viktor [21]4 years ago

3 0

Answer:

Andrew's test score if he got 8 questions wrong = 64 points

Andrew's test score if he got x questions wrong = 80 - 2x

Step-by-step explanation:

Total points of the multiple choice test = 80

Each question = 2 points

Total questions = Total points of the multiple choice test / 2 points

= 80/2

= 40

Total questions = 40

A. What would be Andrew's test score (out of 80) if he got 8 questions wrong

If he got 8 questions wrong out of 40 questions

= Total question points - wrong question points

= 40*2 - 8*2

= 80 - 16

= 64 points

Andrew's test score if he got 8 questions wrong = 64 points

B. What would be his score if he got x questions wrong?

Test points if he got x questions wrong = Total question points - wrong question points

= (40 * 2) - (x * 2)

= 80 - 2x

Andrew's test score if he got x questions wrong = 80 - 2x

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3 years ago

A restaurant interest survey of 230 citizens in a town showed that 80 want a new Chili's, 120 want a new Red Lobster, and 20 wan

mr_godi [17]

The right solution to the given question is " $\frac{2}{23}$ ", " $\frac{6}{23}$ " and " $\frac{5}{23}$ ".

According to the question,

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$b = 20$
$a+b = 80$

By putting the value of "b", we get

$a+20=80$

$a = 80-20$

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By putting the values of "a", "b", "c" and "d", we get

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(a)

P(both Chili's and Red lobster),

= $\frac{b}{a+b+c+d}$

= $\frac{2}{23}$

(b)

P(only chili's),

= $\frac{a}{a+b+c+d}$

= $\frac{6}{23}$

(c)

P(neither),

= $\frac{d}{a+b+c+d}$

= $\frac{5}{23}$

Learn more about probability here:

brainly.com/question/24269622

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3 years ago

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Derek and Mia place two green marbles and one yellow marble in a bag. Somebody picks a marble out of the bag without looking and

cluponka [151]

Answer:

Thus, the expected value of points for Derek and Mia are $\dfrac{-1}{9}$ and $\dfrac{1}{9}$ respectively.

Step-by-step explanation:

Number of green marbles = 2 and Number of Yellow marbles = 1

Then, total number of marbles = 2+1 = 3

A person selects two marbles one after another after replacing them.

So, the probabilities of selecting different combinations of colors are,

$1.\ P(GG)=P(G)\times P(G)\\\\P(GG)=\dfrac{2}{3}\times \dfrac{2}{3}\\\\P(GG)=\dfrac{4}{9}$

$2.\ P(GY)=P(G)\times P(Y)\\\\P(GY)=\dfrac{2}{3}\times \dfrac{1}{3}\\\\P(GY)=\dfrac{2}{9}$

$3.\ P(YG)=P(Y)\times P(G)\\\\P(YG)=\dfrac{1}{3}\times \dfrac{2}{3}\\\\P(YG)=\dfrac{2}{9}$

$4.\ P(YY)=P(Y)\times P(Y)\\\\P(YY)=\dfrac{1}{3}\times \dfrac{1}{3}\\\\P(YY)=\dfrac{1}{9}$

Now, we have that,

If two marbles are of same color, then Mia gains 1 point and Derek loses 1 point.

If two marbles are of different color, then Derek gains 1 point and Mia loses 1 point.

<h3>Also, the expected value of a random variable X is $E(X)=\sum_{i=1}^{n} x_i\times P(x_i)$ .</h3>

Then, the expected value of points for Derek is,

$E(D)= (-1)\times \dfrac{4}{9}+1\times \dfrac{2}{9}+1\times \dfrac{2}{9}+(-1)\times \dfrac{1}{9}\\\\E(D)= \dfrac{-5}{9}+\dfrac{4}{9}\\\\E(D)=\dfrac{-1}{9}$

And the expected value of points for Mia is,

$E(M)= 1\times \dfrac{4}{9}+(-1)\times \dfrac{2}{9}+(-1)\times \dfrac{2}{9}+1\times \dfrac{1}{9}\\\\E(M)= \dfrac{5}{9}-\dfrac{4}{9}\\\\E(M)=\dfrac{1}{9}$ .

Thus, the expected value of points for Derek and Mia are $\dfrac{-1}{9}$ and $\dfrac{1}{9}$ respectively.

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3 years ago

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