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rusak2 [61]
2 years ago
11

Help me on this please ​

Mathematics
1 answer:
gulaghasi [49]2 years ago
5 0
I think +5
Not completely sure
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Which expression is equivalent to the given expression?
Scorpion4ik [409]

None of those is.  The expression   4 In x + In 3 – In r  

is equivalent to the epression  <em>ln( 3x⁴ / r)</em> .

3 0
3 years ago
Find B round to the nearest tenth!!!! laws of cosines!!!!​
AlexFokin [52]

Answer:

32.7°

Step-by-step explanation:

Use the formula for law of cosines, for this question we need so solve for angle B, so use...

b² = a² + c² - 2(a)(c)Cos B

We are given a, b, and c, so plug them in...

55² = 90² + 50² - 2(90)(50)Cos B

Now simplify...

3,025 = 8100 + 2500 - (9000)Cos B

   -7,575 = -(9000)Cos B   (subtract 8100 and 2500 from both sides)    

            0.841666667 = Cos B    (divide both sides by -9000)

       Cos^(-1) 0.841666667 = B  (use cosine inverse function on calculator)

3 0
3 years ago
Help me out please?<br>chapter : exponents and powers​
belka [17]

Answer:

\frac{125}{27}

Step-by-step explanation:

\frac{2^{-4} \times 15^{-3} \times 625}{5^2 \times 10^{-4}}

Lets expand all the composite numbers into prime numbers.

=> \frac{2^{-4} \times (3^{-3} \times 5^{-3}) \times 5^4}{5^2 \times (2^{-4} \times 5^{-4})}

Lets cancel 2^{-4} from numerator and denominator.

=> \frac{3^{-3} \times 5^{-3} \times 5^4}{5^2 \times 5^{-4}}

Using laws of exponents , lets solve this.

=> \frac{3^{-3} \times 5^{(-3 + 4)}}{5^{( 2 - 4)}}

=> \frac{3^{-3} \times 5^{1}}{5^{-2}}

=> 3^{-3} \times 5^{[1 - (-2)]}

=> 3^{-3} \times 5^{3}

=> \frac{5^3}{3^3} = \frac{125}{27}

4 0
3 years ago
Read 2 more answers
Solve the equation plz....................................
Kryger [21]
To find z, you have to divide -3 and 10, which you would get an odd number. That will be your answer for z :)
3 0
3 years ago
Read 2 more answers
The screen shot is the question
oee [108]
Y > -5 is the correct answer.

An open point represents > or <.
The line is to the right, so the symbol is to the left.
4 0
3 years ago
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