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rusak2 [61]
3 years ago
11

Help me on this please ​

Mathematics
1 answer:
gulaghasi [49]3 years ago
5 0
I think +5
Not completely sure
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daniel is using a scale factor of 10 to enlarge a class photo that measures 3.5 inches by 5 inches what are The dimensions Love
Sholpan [36]
35 inches by 50 inches
6 0
3 years ago
Can someone help me with this
VladimirAG [237]

Answer:

  A) 24 ft³

Step-by-step explanation:

The area of the right triangle base is ...

  A = (1/2)(3)(4) = 6 ft²

The volume of the triangular prism is the product of the area of its base (6 ft²) and its height (4 ft).

  V = Bh = (6 ft²)(4 ft) = 24 ft³ . . . . matches choice A

_____

<em>Comment on the triangle</em>

You know the 3-4-5 triangle is a right triangle, because you have seen those numbers many times in relation to the Pythagorean theorem. If you don't know that, then you can check to see by using the Pythagorean theorem:

  5² = 3² +4²

  25 = 9 + 16 . . . . . true; so the triangle is a right triangle

In any event, there are other means for finding the area of the triangle based on the lengths of its sides. You will get the same area result.

Using Heron's formula, s = (a+b+c)/2 = (3+4+5)/2 = 6.

  A = √(s(s -a)(s -b)(s -c)) = √(6(3)(2)(1)) = √36 = 6 . . . . area of base triangle

8 0
4 years ago
Given P(x) = 2x3+ 3x2- x + 4, find P(0) and P(-2).
pshichka [43]

9514 1404 393

Answer:

  P(0) = 4

  P(-2) = 2

Step-by-step explanation:

Put the value where the variable is and do the arithmetic.

  P(0) = 2·0³ +3·0² -0 +4

  P(0) = 4

__

  P(-2) = 2·(-2)³ +3·(-2)² -(-2) +4 = 2(-8) +3(4) +2 +4

  P(-2) = -16 +12 +2 +4

  P(-2) = 2

6 0
3 years ago
On Saturday morning, Malik earned $32. By the end of the afternoon he had earned a total of $63. Which equation represents this
aleksley [76]
X+ 32= 63 that is correct answer
6 0
3 years ago
Add. write your answer in simplest form.<br> -4 _/135 + 7 _/15
Zarrin [17]

\huge\quad\qquad\underline{{\sf Answer}}

Let's solve ~

\qquad \sf  \dashrightarrow \:  - 4 \sqrt{135} + 7 \sqrt{15}

\qquad \tt \dashrightarrow \: - 4 \sqrt{5 \times3 \times 3 \times 3}  + 7 \sqrt{15}

\qquad \tt \dashrightarrow \:( - 4 \times 3) \sqrt{5 \times 3}  + 7 \sqrt{15}

\qquad \tt \dashrightarrow \: - 12 \sqrt{15 }  + 7 \sqrt{15}

\qquad \tt \dashrightarrow \: - 5 \sqrt{15}

7 0
3 years ago
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