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ExtremeBDS [4]
2 years ago
5

Need help finding this answer.

Mathematics
1 answer:
stich3 [128]2 years ago
4 0

Answer:

The area of the dilated square is 28 m^2

Step-by-step explanation:

we  know that whenever any figure is dilated by a factor 'b' units

so, area will be dilated by b^2 units

Here , we are given figure is dilated by 7 units

so, area will be dilated by 7^2

we are given

Area of square is

=\frac{4}{7}

now, we can multiply by 7^2

and we will get area as

A_n=\frac{4}{7}\times 7^2

A_n=28m^2

So,

The area of the dilated square is 28 m^2


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<h3>Answer:   -2w^2 + 25w = 25    or    -2w^2 + 25w - 25 = 0</h3>

================================================================

Explanation:

Refer to the diagram below. The width is w. We have two opposite and parallel sides equal to this. The other two parallel congruent sides are L = 25-2w meters long. We start with the total amount of fencing, and then subtract off the two width values, so 25-w-w = 25-2w.

The area of the rectangle is

Area = length*width

Area = L*W

Area = (25-2w)*w

Area = 25w - 2w^2

Area = -2w^2 + 25w

Set this equal to the desired area (25 square meters) to get

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and we can subtract 25 from both sides to get everything on one side

-2w^2 + 25w - 25 = 0

side note: The two approximate solutions of this equation are w = 1.0961 and w = 11.4039 (use the quadratic formula or a graphing calculator to find this)

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