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3 years ago

Answer the questions below (20 Points)

Mathematics

2 answers:

Volgvan3 years ago

5 0

Answer: for the 12,13,40,95,88,7,95

mean 95,median 83,mode 95

Step-by-step explanation:

Likurg_2 [28]3 years ago

5 0

Answer:

1.Mean (Average) 50

Median 40

Range 88

Mode 95, appeared 2 times

Geometric Mean 32.043846645235

2.Mean (Average) 110

Median 114.5

Range 82

Mode 144, appeared 2 times

Geometric Mean 105.14813572733

3.Mean (Average) 103

Median 85

Range 134

Mode 85, appeared 2 times

Geometric Mean 96.681841043691

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Use the distributive property to multiply the polynomial x (x2+x+x)

pshichka [43]

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3 years ago

If f(x) = -2x + 8 and g(x) = x + 7, what is<br> F•g)(2)?

Blababa [14]

16•7•2 is not the answer

5 0

3 years ago

Solve this equation. 25) v - 6(4v + 6) = -82

grin007 [14]

Answer:

$v = 2$

Step-by-step explanation:

Hi there! I'm glad I was able to help you solve this equation!

Let's start by simplifying both sides of the equation. It's easier to solve it this way!

$v - 6 (4v + 6) = -82$

Distribute:

$v + (-6) (4v) + (-6) (6) = -82$

$v + -24v + -36 = -82$

Combine 'like' terms:

$(v -24v) + (-36) = -82$

$-23v - 36 = -82$

Next, you'll want to add 36 to both sides of the equation.

$-23v-36 + 36 = -82 + 36$

$-23v = -46$

Finally, divide both sides by $-23$ .

$\frac{-23v}{-23} = \frac{-46}{-23}$

$v = 2$

I hope this helped you! Leave a comment below if you have any further questions! :)

7 0

3 years ago

On Texas Avenue between University Drive and George Bush Drive, accidents occur according to a Poisson process at a rate of thre

Zarrin [17]

Answer:

(a) The probability is 0.6514

(b) The probability is 0.7769

Step-by-step explanation:

If the number of accidents occur according to a poisson process, the probability that x accidents occurs on a given day is:

$P(x)=\frac{e^{-at}*(at)^{x} }{x!}$

Where a is the mean number of accidents per day and t is the number of days.

So, for part (a), a is equal to 3/7 and t is equal to 1 day, because there is a rate of 3 accidents every 7 days.

Then, the probability that a given day has no accidents is calculated as:

$P(x)=\frac{e^{-3/7}*(3/7)^{x}}{x!}$

$P(0)=\frac{e^{-3/7}*(3/7)^{0}}{0!}=0.6514$

On the other hand the probability that February has at least one accident with a personal injury is calculated as:

P(x≥1)=1 - P(0)

Where P(0) is calculated as:

$P(x)=\frac{e^{-at}*(at)^{x} }{x!}$

Where a is equivalent to (3/7)(1/8) because that is the mean number of accidents with personal injury per day, and t is equal to 28 because 4 weeks has 28 days, so:

$P(x)=\frac{e^{-(3/7)(1/8)(28)}*((3/7)(1/8)(28))^{x}}{x!}$

$P(0)=\frac{e^{-(3/7)(1/8)(28)}*((3/7)(1/8)(28))^{0}}{0!}=0.2231$

Finally, P(x≥1) is:

P(x≥1) = 1 - 0.2231 = 0.7769

3 0

3 years ago

You plan to buy $12,000 in computers at a local chain store. There are two stores located about the same distance from your offi

wariber [46]

Lets calculate the taxes that would been payed at each city:
city1 = 12000(7%) = 12000(0.07) = 840
city2 = <span>12000(8.5%) = 12000(0.085) = 1020
So if you go to city1 instead of city2, you save 1020 - 840 = 180
So you would save $180 from $12000, that is:
180 out of 12000
= 180/12000
= 0.015
and that is the 1.5%, that is what you could save</span>

4 0

3 years ago