87 1/2 is the answer. hope it help.
Answer:
It has an infinite amount as the decimal keeps going to over 1 million digits and beyond.
Step-by-step explanation:
Answer:
Exact Form:
100/3
Decimal Form:
33.3
Mixed Number Form:
33 1/3
<em><u>i hope this helped at all.</u></em>
Answer:
n = 19.89694
Step-by-step explanation:
You can work the problem using decimal numbers. There is no need to convert everything to integers. Trying to do so just gets you in trouble.
Subtract 2.2 from both sides:
-1.398 -2.200 = n/-5.53
-3.598 = n/-5.53
Now, multiply both sides by -5.53:
(-5.53)(-3.598) = n = 19.89694
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The one rule that cannot be violated in algebra is that <em>you must do the same thing to both sides of the equation</em>.
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Your "solution" so far has a couple of errors. The first is that you have apparently multiplied all of the numbers by 1000. Unfortunately, when you multiply a denominator by 1000, it is the same as dividing by 1000. So, you have multiplied the left side by 1000, multiplied one term on the right by 1000 and divided another term on the right by 1000. This turns the equation into something different than what you started with, and will give a wrong answer.
The second error is that you have subtracted 2200 only from the right side. This, too, will turn the equation into something different than what you started with, and will give a wrong answer.
Answer:
The answer is below
Step-by-step explanation:
Write the coordinates of the vertices after a dilation with a scale factor of 1/5 , centered at the origin.
Transformation is the movement of a point from its initial location to a new location. Types of transformation are rotation, reflection, dilation and translation.
Dilation is the reduction or enlargement in the size of an object by a scale factor (k). If k > 1, it is an enlargement and if k < 1, it is a reduction. If a point A(x, y) is dilated by a factor k, the new point is A'(kx, ky).
Therefore, if the vertices are dilated with a scale factor of 1/5 , centered at the origin. The new point is:
S(5, -10) → S′(1 , -2) T(10, -10) → T′(2 , -2) U(5, 10) → U′(1 , 2)