A(n)=4+4(n-1)
a(n)=4+4n-4
a(n)=4n
76=4n
n=19
The sum of any arithmetic sequence (series are infinite) is:
(a+a(n))(n/2)
The average of the first and last terms times the number of terms, in this case we found that n=19 so:
19(4+76)/2=760
Answer:
275 units^2
Step-by-step explanation:
The formula for the area of trapezoid is:
Area=((b1+b2)/2)*h
In the given trapezoid, as it can be seen
b1=16
h=11
The lower base will be calculated using all the lengths in the lower base
b2=9+16+9
b=34
Putting the values in formula
Area=((16+34)/2)*11
Area=(50/2)*11
Area=25*11
=275 units^2
Answer:
which class do you read now?
<span>(3b - 5x)(a +3) is the answer
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Answer:
Step-by-step explanation:
If the engine torque y (in foot-pounds) of one model of car is given by y=−3.75x^2+23.2x+38.8
The engine speed is at maximum if dy/dx = 0
dy/dx = -2(3.75)x+23.2
dy/dx = -7.5x + 23.2
since dy/dx = 0
0 = -7.5x + 23.2
7.5x = 23.2
x = 23.2/7.5
x = 3.093
Hence the maximum torque is 3.09 rev/min
