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Nataly_w [17]
3 years ago
6

Which lines in the graph have a slope greater than 1 but less than 2? Select all correct answers.

Mathematics
1 answer:
ElenaW [278]3 years ago
8 0

Answer:

Lines 2, 3, 4, and 5

Step-by-step explanation:

I tried my best to calculate the slope of each line. I am not 100% sure about this answer, so don't count on it completely. I hope it helps, but if it is wrong, I apologize.

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Venus is approximately 6.7 x 10^7 miles from the Sun. If the speed of light is approximately 1.86 x 10^5miles per second, about
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6 minutes

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108200,000/300,000 = 360.6 seconds or 6.0 minutes.

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(For earth it is 8.3 minutes)

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Step-by-step explanation:

There is no " Rise over run "

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An elevator in a mine shaft is stopped at a .25 feet below ground level. And then travels 28 feet downward. What equation can be
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Correct question:

An elevator in a mine shaft is stopped at 25 feet below ground level. And then travels 28 feet downward. What equation can be written to find the final position in feet of the elevator in relations to ground level?

Answer:

-53 feets

Step-by-step explanation:

Initial stop point = 25 feets below ground level

Further distance traveled = 28 feets below ground level

Final position in feet = Initial stop point + further distance traveled

Note : distances or point traveled below ground level or downward is represented as negative.

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3 years ago
Find the volume of the solid obtained by rotating the region bounded by the given curves about the specified line. Sketch the re
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Answer:

Step-by-step explanation:

From the first image attached below, we will see the sketch of the curve x = y² & x = 2y

In the picture connected underneath, the concealed locale(shaded region) is bounded by the given curves. Now, we discover the marks of the crossing point of the curves. These curves will cross, when:

y^2 =2 y  \\ \\  or y^2 -2y = 0 \\ \\ y(y-2) = 0  \\ \\ y = 0 \ \  or \ \  y = 2

Thus, the shaded region fall within the interval 0 ≤ y ≤ 2

Now, from the subsequent picture appended we sketch the solid acquired by turning the concealed region about the y-axis.

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A (y) = \pi (outer \ radius)^2 - \pi ( inner \ radius )^2 \\ \\ A(y) = \pi (2y^)2- \pi (y^)^2 \\ \\  A(y) = 4 \pi y^2 - \pi y^4 \\ \\  A(y) = \pi( 4 y^2 -y^4)

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