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2 years ago

For each question (a–e) below, choose one of the answers (i–viii); explain your choice.

Mathematics

1 answer:

Natasha2012 [34]2 years ago

5 0

Answer:

Step-by-step explanation:

given that a deck of cards is shuffled.

we know in a deck there are 52 cards, 13 cards of each variety spade, clubs hearts and dice. Red are 26 and black are 26. kings, will be 4.

(a) the top card is the king of spades and the bottom card is the queen of spades?

(iii) 1/52 × 1/52

Top has 1/52 and bottom has 1/52 and these are independent.

(b) the top card is the king of spades and the bottom card is the king of spades?

(viii) None of the above

Because it is impossible.

(iv) 1/52 + 1/52

This is the sum of probabilities because there is no common event for these two.

(d) the top card is the king of spades or the bottom card is the queen of spades?

(ii) 1/52 + 1/51 (once king of spades is there, then probability is 1/51 for bottom card)

(e) of the top and bottom cards, one is the king of spades and the other is the queen of spades?

(vii) 2/52 × 1/51

Because this is twice of probability d.

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Given the preimage and image,find the dilation scale factor.

Oliga [24]

Answer:

The dilation scale factor is $\frac{1}{2}$ .

Step-by-step explanation:

The image is the dilated form of its preimage if and only if the following conditions are observed:

1) $K' = \alpha_{1} \cdot K$

2) $T' = \alpha_{2} \cdot T$

3) $P' = \alpha_{3} \cdot P$

4) $J' = \alpha_{4} \cdot J$

5) $\alpha_{1} = \alpha_{2} = \alpha_{3} = \alpha_{4}$

If we know that $K = (2, 0)$ , $K' = (1, 0)$ , $T = (3, 0)$ , $T' = (1.5,0)$ , $P = (1, 5)$ , $P' = (0.5, 2.5)$ , $J = (0, 3)$ and $J' = (0, 1.5)$ , then the coefficients are, respectively:

$\alpha_{1} = \frac{1}{2}$ , $\alpha_{2} = \frac{1}{2}$ , $\alpha_{3} = \frac{1}{2}$ , $\alpha_{4} = \frac{1}{2}$

As $\alpha_{1} = \alpha_{2} = \alpha_{3} = \alpha_{4}$ , we conclude that the dilation scale factor applied in the preimage is equal to $\frac{1}{2}$ .

7 0

2 years ago

A box has 11 marbles, 3 of which are white and 8 of which are red. A sample of 4 marbles are selected randomly from the box with

aliina [53]

14/99

Select 1 marble; the chance that it is white is 4/12. Select a 2nd marble; the chance that it is white is 3/11. Select a 3rd; the chance it is white is 2/10. Select a 4th; the chance it is red is 8/9. Select a 5th; the chance it is red is 7/8. The chance of getting this specific set of 5 marbles in this order is (4/12)×(3/11)×(2/10)×(8/9)×(7/8)=(2×7)/(11×10×9).

This specific set could occur in the permutation of 5 things taken 5 at a time where 3 are identical (white), and the other 2 are also identical (red). The formula for this is 5!/(3!2!)=10.

Combining the chance of getting white, white, white, red, red with the number of ways 3 white and 2 red could have been distributed in the draw of 5 marbles gives the answer:

{(2×7)/(11×10×9)}×10=14/99

A similar process will show that the chance of getting 5 red marbles is 7/99; 4 white and 1 red is 1/99; 2 white and 3 red is 42/99; and 1 white and 4 red is 35/99.

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2 years ago

The secret to football betting

padilas [110]

What is the SECRET to football BETTING ??

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2 years ago

Please help<br><br> 23 - 7 3/5

kompoz [17]

Answer:15 2/5

Step-by-step explanation:

23 - 7 = 16

16 - 3/5 → 15 5/5 - 3/5 = 15 2/5

6 0

2 years ago

What is the value of a?

Juli2301 [7.4K]

Actually, the answer is not A, if you're saying A is the first choice above. That's incorrect. You will need to use the Geometric mean for right triangles here to figure out what the value of a is. We will use this form: $\frac{YZ}{WZ} = \frac{WZ}{XZ}$ . We have a value for YZ of 3; side a is XZ. That means in order to solve this we need WZ, which we can find using pythagorean's theorem. 3^2 + 4^2 = c^2 and 9 + 16 = c^2 and c = 5. Now we fill in accordingly: $\frac{3}{5}= \frac{5}{XZ}$ . Cross-multiply to get 3XZ=25 and side XZ is $\frac{25}{3}$ . XZ is 25/3 and YZ is 3, so 25/3 - 3 = XY. That means that XY (side a) = 16/3 or 5 1/3, choice B, or the second one down.

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2 years ago