Question

A fruit stand has to decide what to charge for their produce. They need $10 for 44 apples and 44 oranges. They also need $15 for 66 apples and 66 oranges. We put this information into a system of linear equations.

Answer 1

Step-by-step explanation:

Let x be the price of an apple and y be the price of an orange.

We have been given that a fruit stand need $10 for 4 apples and 4 oranges. We can represent this information as:

$4x+4y=10...(1)$

We are also told that they need $15 for 6 apples and 6 oranges. We can represent this information as:

$6x+6y=15...(2)$

Therefore, our desired system of equations will be:

$4x+4y=10...(1)$

$6x+6y=15...(2)$