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Licemer1 [7]
3 years ago
12

PLEASE HELP!! Whoever is correct I will award Brainliest!! I need the answer to all questions for Brainliest. What is the median

of the data set?
{12, 15, 18, 20, 22, 23, 24, 40, 45}


What is the first quartile, Q1, of the data set?



{24, 29, 32, 35, 40, 50, 62}



What is the median of the data represented by the box plot?

A number line ranging from 0 to 143.75 with a box encompassing the numbers 12.5, 20, and 65.

Mathematics
2 answers:
olya-2409 [2.1K]3 years ago
8 0
Median: 22
Q1: 29
sorry but i don't know the answer to the last question
nordsb [41]3 years ago
3 0

Answer:

Step-by-step explanation:

The data set is already in ascending order with 9 entries

Hence median is 5th one = 22

I quartile = 8/4 =2nd entry = 29

3) median of data by box plot

o to 143.75

Median is middle entry = 20

----------------------

4) Last two questions as

How many hours will the museum give this week? and

How many visitors came to this museum each month last year?

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olasank [31]
7/8 = y/11

so multiply 11 to both sides of the equation

so now its (7*11)/8= y 

y=77/8

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Whats 2 plus 2? Whats 10 plus 10? And whats 8 plus 8?
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\bold{THE  \: ADDITION}

or addition is the mathematical operation of composition that consists of combining or adding two or more numbers to obtain a final or total quantity. The addition also illustrates the process of joining two collections of objects in order to obtain a single collection

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\red{ \huge{ \texttt{ACTIVITY}}}

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faust18 [17]

6.\\\text{We know}\ 9=3^2.\ \text{Therefore}\\\\9^2=(3^2)^2\\\\\text{use}\ (a^n)^m=a^{nm}\\\\9^2=(3^2)^2=3^{2\cdot2}=3^4\\\\\boxed{3^4=9^2}\\=================

7.\\METHOD\ 1:\\\\\sqrt{7^4}=\sqrt{7^{2\cdot2}}\\\\\text{use}\ (a^n)^m=a^{nm}\\\\=\sqrt{(7^2)^2}\\\\\text{use}\ \sqrt{a^2}=a\ \text{for}\ a\geq0\\\\=\boxed{7^2}\\\\METHOD\ 2:\\\\\text{use}\ a^\frac{m}{n}=\sqrt[n]{a^m}\\\\\sqrt{7^4}=7^\frac{4}{2}=\boxed{7^2}\\=================

8.\\5^a\times5^b=5^{11}\\\\a)\\\text{use}\ a^n\times a^m=a^{n+m}\\\\5^a\times5^b=5^{a+b}\\\\5^{a+b}=5^{11}\Rightarrow a+b=11\\\\11\ \text{is odd. The sum of even and odd is odd. Therefore}\ a\ \text{and}\ b\ \text{can't be even.}\\--------------------\\\\b)\\5\ \text{solutions}\\\\11=5+6\\11=4+7\\11=3+8\\11=2+9\\11=1+10

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