Answer:
Step-by-step explanation:
"one over threep + 15":
Answer:
Step-by-step explanation:
The problem relates to filling 8 vacant positions by either 0 or 1
each position can be filled by 2 ways so no of permutation
= 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2
= 256
b )
Probability of opening of lock in first arbitrary attempt
= 1 / 256
c ) If first fails , there are remaining 255 permutations , so
probability of opening the lock in second arbitrary attempt
= 1 / 255 .
Answer:
Step-by-step explanation:
Answer:
D. a−b=10 a=3b+4
Step-by-step explanation:
Difference between a and b means to subtract b from a
We have,
a-b=10
a is 4 more than 3 times b
4 more than means to add 4
3 times b means to multiply b by 3
Therefore, a=3 times b + 4
a=3b+4
a - b=10; a=3b+4
Answer: x2= 6
FYI: The x2 is x squared
Step-by-step explanation:
Simplifying
4x2 + 7 = 31
Reorder the terms:
7 + 4x2 = 31
Solving
7 + 4x2 = 31
Solving for variable 'x'.
Move all terms containing x to the left, all other terms to the right.
Add '-7' to each side of the equation.
7 + -7 + 4x2 = 31 + -7
Combine like terms: 7 + -7 = 0
0 + 4x2 = 31 + -7
4x2 = 31 + -7
Combine like terms: 31 + -7 = 24
4x2 = 24
Divide each side by '4'.
x2 = 6
Simplifying
x2 = 6
