<h2>The graph of y = ax^2 + bx + c
</h2><h2>A nonlinear function that can be written on the standard form
</h2><h2>ax2+bx+c,where a≠0
</h2><h2>All quadratic functions has a U-shaped graph called a parabola. The parent quadratic function is
</h2><h2>
y=x2
</h2><h2>
The lowest or the highest point on a parabola is called the vertex. The vertex has the x-coordinate
</h2><h2>x=−b2a
</h2><h2>The y-coordinate of the vertex is the maximum or minimum value of the function.
</h2><h2>a > 0 parabola opens up minimum value
</h2><h2>a < 0 parabola opens down maximum value
</h2><h2>
A rule of thumb reminds us that when we have a positive symbol before x2 we get a happy expression on the graph and a negative symbol renders a sad expression.
</h2><h2>The vertical line that passes through the vertex and divides the parabola in two is called the axis of symmetry. The axis of symmetry has the equation
</h2><h2>x=−b2a
</h2><h2>The y-intercept of the equation is c.
</h2><h2>
When you want to graph a quadratic function you begin by making a table of values for some values of your function and then plot those values in a coordinate plane and draw a smooth curve through the points.</h2>
X= 1 .........................
The confidence interval would be
.
We use the formula
, where
, with p being the sample proportion and N being the sample size.
First we find the z-score associated with this level of confidence:
Convert 95% to a decimal: 95/100 = 0.95
Subtract from 1: 1-0.95 = 0.05
Divide by 2: 0.05/2 = 0.025
Subtract from 1: 1-0.025 = 0.975
Using a z-table (http://www.z-table.com) we see that this value is associated with a z-score of 1.96.
Since 578/720 said yes, this gives us p=0.80:
This gives us
Use the x and y values from your point and the h and k from the center to write the equation you need to solve for r. The general form of the equation for a circle is
. We will fill in accordingly:
. Solve for r to get that