Evaluate. -18.6 -18.6 -1 Enter your answer in the box.

Mathematics

1 answer:

VladimirAG [237]3 years ago

4 0

Answer:

18.6

Step-by-step explanation:

You might be interested in

What does the expression look like when we substitute the given values for x, y, and z into the expression?

Greeley [361]

The expression will look like 9-(3+2) and will evaluate to 4

Step-by-step explanation:

We have to put the values of x, y and z in the given expression to find the result.

Given:

$x-(y+z)$

And

$x=9\\y=3\\z=2$

Putting the values

$9-(3+2)\\=9-5\\=4$

The expression will look like 9-(3+2) and will evaluate to 4

Keywords: Expressions, Evaluation

Learn more about evaluation at:

#learnwithBrainly

5 0

4 years ago

7-18 use part 1 of the fundamental theorem of calculus to find the derivative of the function.

blondinia [14]

$\displaystyle h(x)=\int\limits_{1}^{\sqrt{x}}~\cfrac{z^2}{z^4+1}dz~\hspace{10em}\cfrac{dh}{du}\cdot \stackrel{chain~rule}{\cfrac{du}{dx}\implies \cfrac{dh}{dx}} \\\\[-0.35em] ~\dotfill\\\\ u=\sqrt{x}\implies \cfrac{du}{dx}=\cfrac{1}{2\sqrt{x}} \\\\[-0.35em] ~\dotfill$

$\cfrac{dh}{dx}\implies \displaystyle \cfrac{d}{du}\left[ \int\limits_{1}^{u}~\cfrac{z^2}{z^4+1}dz \right]\cdot \cfrac{1}{2\sqrt{x}}\implies \left[ \cfrac{u^2}{u^4+1} \right]\cdot \cfrac{1}{2\sqrt{x}} \\\\\\ \stackrel{substituting~back}{\left[ \cfrac{(\sqrt{x})^2}{(\sqrt{x})^4+1} \right]\cdot \cfrac{1}{2\sqrt{x}}}\implies \cfrac{x}{x^2+1}\cdot \cfrac{1}{2\sqrt{x}}\implies \cfrac{\sqrt{x}}{2x^2+2}$