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sweet-ann [11.9K]
3 years ago
7

Z - 3( z + 2 ) = -6 - 2z

Mathematics
2 answers:
Salsk061 [2.6K]3 years ago
8 0

Answer:

0

Step-by-step explanation:

just multiply and bring the numbers to the other sides and both equal 0

Arlecino [84]3 years ago
3 0

Answer: depends (read explanation)

Either 0=0 (doubt) or:

Z= -3

Step-by-step explanation:

1.Assuming that whole line is the equation:

Group like terms. Put all z terms on one side and normal numbers on the other.

There are brackets so remove them first.

Z-3z-6=-6-2z

-2z+2z=-6+6

0=0

2. If you started the question already and got to -6-2z=0:

-6=2z

Z=-6/2

Z=-3

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WHOEVER GETS THIS RIGHT IN 3 MINUTES GETS THE BRAINLIEST!! Four times the sum of a number and 15 is at least 120. Let x represen
larisa [96]

Hey there!

Let's call this "number" x. We want four times the sum of this number and 15 to equal at least 120.

Therefore, we want this number times four plus fifteen to be greater than or equal to 120. We have:

4(x+15)\geq 120

Distribute:

4x + 60 \geq 120

Subtract:

4x\geq 60

Divide:

x\geq 15

Your answer is C.

Hope this helps!

7 0
3 years ago
Rewrite the expression in the form a^n.<br> 1/a^-5/6
Sav [38]

Step-by-step explanation:

here's the answer to your question

7 0
3 years ago
Read 2 more answers
Let f be the function given by the sum of the first three nonzero terms of this series. The maximum value of |lnx-f(x)| for .3&l
kodGreya [7K]

Answer:

Step-by-step explanation:

f(x) = sin(4x)f'    = 4 cos(4x)f''   = -16 sin(4x)f'''  = -64 cos(4x)f⁽⁴⁾ = 256 sin(4x)f⁽⁵⁾ = 1024 cos(4x)The 4-th order Taylor series expansion isf(x+h) = f(x) + hf'(x) + (h²/2!)f''(x) + (h³/3!)f'''(x) + (h⁴/4!)f⁽⁴⁾(x) + ...The Maclaurin series is obtained by setting x = 0.Note that sin(0) = 0 and cos(0) = 1.The non zero terms aref(h) = 4h - (4h)³/3! + (4h)⁵/5! - (4h)⁷/7! + ...Answer: f(x) =4x- 4/3+4x/5+4x7

HOPE THIS HELPED ;3 please mark Brainliest

4 0
3 years ago
could someone help me solve this equations with both comparison and elimination methods: 2(x+y)=120 and 2(2x+y/3)=170​
Gnom [1K]

Answer:

y=21 X=39

Step-by-step explanation:

expand brackets on first equation: 2x+2y=120

now divide the second equation by 2 on both sides:

2x+y/3=85

then subtract the second equation from the first equation

so (2x+2y) - (2x+y/3)

the 2x on both sides cancel out and you get 5/3 y

this is equal to the sum of the first equation subtract the second equation which is 35

divide both sides by 5/3 and you get

y=21

substitute y in the first equation and you get X=39

4 0
2 years ago
Are they scaled copies or not? If so how do I find out?
Alenkinab [10]

1) <u>Find the length of the diagonals of the greater rhombus</u>

NJ=9 units

XY=6 units

Find the the ratio

NJ/XY=9/6-------> 3/2

2) <u>Find the length of the diagonals of the smaller rhombus</u>

HS=6 units

ZC=4 units

Find the the ratio

HS/ZC=6/4-------> 3/2

so

NJ/XY=HS/ZC--------> the rhombus are similar

the scale factor is equal to ------> 3/2=1.5

measure greater rhombus =scale factor*measure smaller rhombus

measure greater rhombus =1.5*measure smaller rhombus

measure smaller rhombus=(measure greater rhombus/1.5)

therefore

<u>the answer is</u>

Yes , they are a scaled copies and the scale factor is equal to 1.5


8 0
4 years ago
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