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belka [17]
2 years ago
13

Simplify the following ratios:

Mathematics
1 answer:
jenyasd209 [6]2 years ago
6 0
A) 3:4
b) 2:7
c) 3.5
d) 2:3
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A cell phone measure 10 cm long,6 cm long,and 2cm high what is the volume of the cell phone
vaieri [72.5K]
The are of the cell phone is 184 hope this helped
3 0
2 years ago
Which is the simplified form of r^-7 + s^-12
makkiz [27]

Answer:

The simplified form of r^-7 + s^-12 is ----> 1/r^7 + 1/s^12

Step-by-step explanation:

3 0
3 years ago
Find the midpoint of the line segment whose endpoints are (2.6,5.1) and (3,4.7).
svp [43]

Answer:

Mid point is: (2.8;4.9)

Step-by-step explanation:

To find midpoint of a line segment we can use the general equation:

Mid=\frac{x_1+x_2}{2} ;\frac{y_1+y_2}{2}

Where the point of the line are: (x₁;y₁) and (x₂;y₂).

In the problem, x₁ = 2.6, y₁ = 5.1 and x₂ = 3 and y₂ = 4.7. Replacing in the equation:

Mid=\frac{2.6+3}{2} ;\frac{5.1+4.7}{2}

<h3>Mid point is: (2.8;4.9)</h3>

7 0
3 years ago
Please help me:)
Delicious77 [7]

Answer:

Start at the - origin

Move 3 units - right

Move 6 units - up

6 0
2 years ago
For each of the following functions, determine if they are injective. Also determine if theyare surjective. Also determine if th
timurjin [86]

Answer:

Check below

Step-by-step explanation:

1. Definition for intervals

(a,b)=\left \{ x\in\Re : a

2. Functions

1) \Re \rightarrow \Re \\ f(x)=x

Let's perform graph tests.

That's an one to one, injective function. Look how any horizontal line touches that only once. Also, It's a surjective and a bijective one.

2)\Re\geq0\rightarrow\Re , f(x)=x+1\\

Injective, surjective and bijective.

Injective: a horizontal line crosses the graph in one point.

3)f:\Re\geq 0\rightarrow\Re, f(x) = cos(x)

The cosine function is not injective, bijective nor surjective.

4)f:\Re\rightarrow\Re \:f(x)=ex

Since e, is euler number it's a constant. It's also injective, surjective and bijective.

5)  Quite unclear format

6) \:f:\Re\rightarrow(0,\infty), f(x) =ex

Despite the Restriction for the CoDomain, the function remains injective, surjective and therefore bijective.

7) f:\Re\geq 0 \rightarrow  \Re\geq0, f(x) =x^{4}

Not injective nor surjective therefore not bijective too.

8).f:\{-1,2,-3\}}\rightarrow \{1,4,9\}, f(x) =x^{2}

f(-1)=1, f(2)=4, f(-3)=9

Injective (one to one), Surjective,  and Bijective.

10) f:\Re\geq 0\rightarrow [-1,1], f(x)= cos(x)\\-1=cos(x) \therefore x=\pi,3\pi,5\pi,etc.

Surjective.

11.f:R\geq 0[-1,1], f(x) = 0\\

Surjective

12.f: US Citizens→Z, f(x) = the SSN of x.

General function

13.f: US Zip Codes→US States, f(x) = The state that x belongs to.

Surjective

7 0
2 years ago
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