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2 years ago

Simplify the following ratios:

Mathematics

1 answer:

jenyasd209 [6]2 years ago

6 0

A) 3:4
b) 2:7
c) 3.5
d) 2:3

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A cell phone measure 10 cm long,6 cm long,and 2cm high what is the volume of the cell phone

vaieri [72.5K]

The are of the cell phone is 184 hope this helped

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2 years ago

Which is the simplified form of r^-7 + s^-12

makkiz [27]

Answer:

The simplified form of r^-7 + s^-12 is ----> 1/r^7 + 1/s^12

Step-by-step explanation:

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3 years ago

Find the midpoint of the line segment whose endpoints are (2.6,5.1) and (3,4.7).

svp [43]

Answer:

Mid point is: (2.8;4.9)

Step-by-step explanation:

To find midpoint of a line segment we can use the general equation:

$Mid=\frac{x_1+x_2}{2} ;\frac{y_1+y_2}{2}$

Where the point of the line are: (x₁;y₁) and (x₂;y₂).

In the problem, x₁ = 2.6, y₁ = 5.1 and x₂ = 3 and y₂ = 4.7. Replacing in the equation:

$Mid=\frac{2.6+3}{2} ;\frac{5.1+4.7}{2}$

<h3>Mid point is: (2.8;4.9)</h3>

7 0

3 years ago

Please help me:)

Delicious77 [7]

Answer:

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Move 3 units - right

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2 years ago

For each of the following functions, determine if they are injective. Also determine if theyare surjective. Also determine if th

timurjin [86]

Answer:

Check below

Step-by-step explanation:

1. Definition for intervals

$(a,b)=\left \{ x\in\Re : a$

2. Functions

1) $\Re \rightarrow \Re \\ f(x)=x$

Let's perform graph tests.

That's an one to one, injective function. Look how any horizontal line touches that only once. Also, It's a surjective and a bijective one.

2) $\Re\geq0\rightarrow\Re , f(x)=x+1\\$

Injective, surjective and bijective.

Injective: a horizontal line crosses the graph in one point.

3) $f:\Re\geq 0\rightarrow\Re, f(x) = cos(x)$

The cosine function is not injective, bijective nor surjective.

4) $f:\Re\rightarrow\Re \:f(x)=ex$

Since e, is euler number it's a constant. It's also injective, surjective and bijective.

5) Quite unclear format

$6) \:f:\Re\rightarrow(0,\infty), f(x) =ex$

Despite the Restriction for the CoDomain, the function remains injective, surjective and therefore bijective.

$7) f:\Re\geq 0 \rightarrow \Re\geq0, f(x) =x^{4}$

Not injective nor surjective therefore not bijective too.

$8).f:\{-1,2,-3\}}\rightarrow \{1,4,9\}, f(x) =x^{2}$

$f(-1)=1, f(2)=4, f(-3)=9$

Injective (one to one), Surjective, and Bijective.

$10) f:\Re\geq 0\rightarrow [-1,1], f(x)= cos(x)\\-1=cos(x) \therefore x=\pi,3\pi,5\pi,etc.$

Surjective.

$11.f:R\geq 0[-1,1], f(x) = 0\\$

Surjective

12.f: US Citizens→Z, f(x) = the SSN of x.

General function

13.f: US Zip Codes→US States, f(x) = The state that x belongs to.

Surjective

7 0

2 years ago