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nalin [4]
3 years ago
5

Write the number in the form a+bi square root of -64+2?

Mathematics
1 answer:
Igoryamba3 years ago
5 0

Answer:

\sqrt{-64}+2=2+8i

Step-by-step explanation:

i=\sqrt{-1}\\\\\sqrt{-64}=\sqrt{(64)(-1)}\qquad\text{use}\ \sqrt{ab}=\sqrt{a}\cdot\sqrt{b}\ for\ a\geq0\ and\ b\geq0\\\\=\sqrt{64}\cdot\sqrt{-1}=8\cdot i=8i\\\\\text{Therefore:}\\\\\sqrt{-64}+2=8i+2=2+8i

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Slav-nsk [51]
Answer= 120
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3 years ago
How do u get the area of a circle?
galina1969 [7]

Answer: πr^2

Step-by-step explanation:

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then multiply the radius squared by π(pie) which is 3.14 or use a calculator.

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Joseph owns v video games. Harry owns 10 fewer than two times the number of video games that Joseph owns. Which expression repre
Tomtit [17]

Answer:

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8 0
2 years ago
Evelyn's made a cake in the shape of a circus tent the cake consisted of a cylinder and a cone .The height of the cone is half t
Lera25 [3.4K]
The volume of the cake is 1470 in³. 
volume of a cylinder = πr² x height
(Think about how a cylinder is basically a bunch of circles stacked on top of each other. To find the volume, first you need the area of the circle (πr², then you multiply by how many circles you are stacking on top of each other (height)) 

we know the diameter of the cylinder is 12 in. and the radius is half of the diameter. 
half of 12 is 6, therefore the radius is 6 in. or r = 6 
Assuming pi is 3.14, solve for the height of the cylinder
1470 = (3.14)(6²)(height)
1470 = 3.14 x 36 x height
1470 = 113.04 x height
height ≈ 13 in

Now that we know the height of the cylinder is about 13 in., we know the height of the cone, because the problem says that the height of the cone is half the height of the cylinder. 
half of 13 is 6.5, therefore the height of the cone is 6.5 
the radius of the cone is the same as that of the cylinder, 6 in. 

volume of a cone = πr² × (height ÷ 3)

volume of the cone = (3.14)(6²)(6.5 ÷ 3)
volume of the cone = (3.14)(36)(2.16666)
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1470 + 244.92 = 1714.92 in³



6 0
4 years ago
How does this polynomial identity work on numerical relationships?<br> (y + x) (ax + b)
Serggg [28]

Let us take 'a' in the place of 'y' so the equation becomes

(y+x) (ax+b)

Step-by-step explanation:

<u>Step 1:</u>

(a + x) (ax + b)

<u>Step 2: Proof</u>

Checking polynomial identity.

(ax+b )(x+a) = FOIL

(ax+b)(x+a)

ax^2+a^2x is the First Term in the FOIL

ax^2 + a^2x + bx + ab

(ax+b)(x+a)+bx+ab is the Second Term in the FOIL

Add both expressions together from First and Second Term  

= ax^2 + a^2x + bx + ab

<u>Step 3: Proof </u>

(ax+b)(x+a) = ax^2 + a^2x + bx + ab

Identity is Found .

Trying with numbers now

(ax+b)(x+a) = ax^2 + a^2x + bx + ab

((2*5)+8)(5+2) =(2*5^2)+(2^2*5)+(8*5)+(2*8)

((10)+8)(7) =(2*25)+(4*5)+(40)+(16)

(18)(7) =(50)+(20)+(56)

126 =126

3 0
4 years ago
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