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svet-max [94.6K]
2 years ago
9

An envelope contains $1.20 in dimes and nickels. if the dimes were quarters and the nickels were dimes, there would be $1.35 mor

e in the envelope. How many nickels are in the envelope?
Mathematics
1 answer:
balu736 [363]2 years ago
7 0

The nickels in the envelope is $0. 12

<h3>How to determine the number</h3>

From the information given, we have that;

Dimes + nickels = $1. 20

1/4 dimes + dimes = $ 1. 35

Let dimes = d

Nickels = n

d + n = 1. 20    equation a

d/4 + d = 1. 35   equation b

Make 'd' subject from equation a

d = 1. 20 - n

Substitute into equation b

1. 20 - n/ 4 + 1. 20 - n = 1. 35

0. 3 - 0. 25n + 1. 20 - n = 1. 35

collect like terms

- 1. 25n = 1. 35 - 1. 5

- 1. 25 = - 0. 15

n = -0. 15/ -1. 25

n = 0. 12

Thus, the number of nickels in the envelope is $0. 12

Learn more about algebraic expressions here:

brainly.com/question/4344214

#SPJ1

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