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3 years ago

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11.REINFORCE The lengths of three sides of a triangle are 2x, 3x - 4, and x+4. Find a value of x that makes the triangle equilat

eral.

1 answer:

mash [69]3 years ago

5 0

Answer:

x=4

Step-by-step explanation:

It suffices to equate any two sides and then check whether the solution is valid for the third side.

Taking 2x and 3x-4 and equating:

2x = 3x-4

x = 4

This means the sides are both of length 8. Now check whether for x=4 the third side is also of length 8:

x+4=4+4=8

which indeed works out confirming x=4 being a valid solution

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Answer:

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Step-by-step explanation:

Given : $\dfrac{\sqrt 3 -1}{\sqrt 3+1}+\dfrac{\sqrt 3+1}{\sqrt 3-1}=a+\sqrt 3 b$

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Solving LHS of the given equation,

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Since,

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or

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3 years ago

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kirill115 [55]

Answer:

The triangle ABC is an isosceles right triangle

Step-by-step explanation:

we have

The coordinates of triangle ABC are

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we know that

An isosceles triangle has two equal sides and two equal internal angles

The formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

step 1

Find the distance AB

substitute in the formula

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step 2

Find the distance BC

substitute in the formula

$d=\sqrt{(7-5)^{2}+(-1-2)^{2}}$

$d=\sqrt{(2)^{2}+(-3)^{2}}$

$dBC=\sqrt{13}\ units$

step 3

Find the distance AC

substitute in the formula

$d=\sqrt{(7-2)^{2}+(-1-0)^{2}}$

$d=\sqrt{(5)^{2}+(-1)^{2}}$

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step 4

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