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elena55 [62]
3 years ago
13

ASAP What is the lateral area of this regular octagonal pyramid?? Explain your answer if you can plz thanks

Mathematics
2 answers:
horsena [70]3 years ago
6 0

Answer:

Hello! The correct answer is 298.7 cm^{2}

Step-by-step explanation:

I am just confirming!

Archy [21]3 years ago
3 0
The lateral area would be 298.7 cm².

The lateral area is the area of all of the lateral faces of the pyramid.  There are 8 triangles making up the lateral faces.  Each has a base of 6.6.  The formula for the area of a triangle is

A=1/2bh,

so we still need the height of the triangle.

The height of each lateral triangle is the slant height of the pyramid.  The slant height of the pyramid forms a right triangle with the height of the pyramid and the "radius" as it were of the pyramid.  Thus we use the Pythagorean theorem:

8²+8²=h²
64+64=h²
128=h²
√128=√(h²)
8√2 = h

Substituting this into our area formula we have:
A=1/2(6.6)(8√2)

We will go ahead and multiply this by 8, since there are 8 lateral faces:
LA=8(1/2)(6.6)(8√2)
LA = 298.7
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oksian1 [2.3K]

Given :-

  • a² - 2a - b² = 0
  • 2b + 2ab = 0

To find :-

  • Value of a and b .

Solution :-

<u>Taking</u><u> </u><u>second</u><u> </u><u>equation</u><u>:</u><u>-</u>

  • 2b + 2ab = 0
  • 2b ( 1 + a ) = 0
  • 2b = 0 or (1+a) = 0
  • b = 0 , a = -1

<u>Substitute</u><u> </u><u>in </u><u>first </u><u>equation</u><u> </u><u>:</u><u>-</u><u> </u>

  • a² - 2a - b² = 0

<u>When </u><u>b </u><u>=</u><u> </u><u>0</u><u> </u><u>,</u>

  • a² - 2a - 0² = 0
  • a² - a = 0
  • a( a -1) =0
  • a = 0 , 1

<u>When </u><u>a </u><u>=</u><u> </u><u>-</u><u>1</u><u> </u><u>,</u>

  • (-1)² - 2*(-1) - b² = 0
  • 1 + 2 - b² = 0
  • b² = 3
  • b = ±√3

<u>Answer </u><u>:</u><u>-</u><u> </u>

  • a = 0,1 ; b = 0
  • a = -1 , b = ±√3
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Answer and Explanation:

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For number 4, I'd suggest Graph 3.

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